十六进制字符串转char数组

[绝世酱油瓶]

RT、例如我输入"1A023b4d5c6f9",没有任何分符，如何如何获取这个十六进制的字符串，然后转换成unsigned char的数组。

例如：
unsigned char tmp[7];
tmp[0]=0x1A;
tmp[1]=0x02;
.........这样

[青松2]

先每两个字符截取出来，再转换成数值呗

[杀意已决]

        CString str(_T("1A023b4d5c6f9"));
        char tmp[6];
	char arr[2];
	int j = 0;
	int k = 0;
	for(int i=0; i<str.GetLength(); i++)
	{
		if (j == 0)
		{
			arr[j] = str.GetAt(i);
			j = 1;
		}
		else
		{
			arr[j] = str.GetAt(i);
			int tempNum = atoi(arr);
			tmp[k] = tempNum/10*16 + tempNum%10;
			k++;
			j = 0;
		}
	}

[杀意已决]

    CString str(_T("1A023b4d5c6f9"));
    char tmp[7];
    char arr[2];
    int j = 0;
    int k = 0;
    for(int i=0; i<str.GetLength(); i++)
    {
        if (j == 0)
        {
            arr[j] = str.GetAt(i);
            j = 1;
        }
        else
        {
            arr[j] = str.GetAt(i);
            int tempNum = atoi(arr);
            tmp[k] = tempNum/10*16 + tempNum%10;
            k++;
            j = 0;
        }
    }
tmp[6] = '\0';

[shen_wei]

CString str(_T("1A023b4d5c6f9")); str.GetBufferSetLength(2); int nPos = _wtoi(str); char temp = nPos; 以上只是例子

[shen_wei]

CString str(_T("1A023b4d5c6f9"));
	CString sTemp = str;	
	int nlen = str.GetLength()/2;\\考虑这个能否整除
	char *Buf = new char[nlen];
	ZeroMemory(Buf,nlen);
	for (int i =0;i<nlen;i++)
	{
		sTemp.GetBufferSetLength(2);
		Buf =(char) _wtoi(sTemp);
		str.Delete(0,2);
		sTemp.ReleaseBuffer();
		
	}

[绝世酱油瓶]

引用 1 楼 lhfslhfs 的回复:

先每两个字符截取出来，再转换成数值呗

怎么转成数值啊

[绝世酱油瓶]

引用 5 楼 shen_wei 的回复:

CString str(_T("1A023b4d5c6f9"));
	CString sTemp = str;	
	int nlen = str.GetLength()/2;\\考虑这个能否整除
	char *Buf = new char[nlen];
	ZeroMemory(Buf,nlen);
	for (int i =0;i<nlen;i++)
	{
		sTemp.GetBufferSetLength(2);
		Buf =(char) _wtoi(sTemp);
		str.Delete(0,2);
		sTemp.ReleaseBuffer();
		
	}

'_wtoi' : cannot convert parameter 1 from 'class CString' to 'const unsigned short *' 这个函数用不了哦

[lessasd1]

引用 1 楼 lhfslhfs 的回复:

先每两个字符截取出来，再转换成数值呗

美女 求交往 教我编程！

[骑着蜗牛追乌龟]

全部读进来，然后两两截取，再转换保存到char里面。

[wumn29]

short int HexChar2Dec(char c)  
{  
    if ( '0'<=c && c<='9' ) {  
        return short(c-'0');  
    } else if ( 'a'<=c && c<='f' ) {  
        return ( short(c-'a') + 10 );  
    } else if ( 'A'<=c && c<='F' ) {  
        return ( short(c-'A') + 10 );  
    } else {  
        return -1;  
    }  
} 

int str2Num16(const char* str)
{
  return (str[i+1] == '\0') ? HexChar2Dec(str[i]) : HexChar2Dec(str[i])*16+HexChar2Dec(str[i+1]);
}
void Parse()
{	
         char hexstr[] = "1A023b4d5c6f9";
	int len = (strlen(hexstr)%2 == 0) ? strlen(hexstr)/2 : (strlen(hexstr)/2+1);
	unsigned char hex[128] = {0};
	for (int i = 0; i < len; ++i)
	{
		int idx = i*2;
		hex[i] = str2Num16(hexstr+idx);
	}
}

[wumn29]

引用 10 楼 wumn29 的回复:

short int HexChar2Dec(char c)  
{  
    if ( '0'<=c && c<='9' ) {  
        return short(c-'0');  
    } else if ( 'a'<=c && c<='f' ) {  
        return ( short(c-'a') + 10 );  
    } else if ( 'A'<=c && c<='F' ) {  
        return ( short(c-'A') + 10 );  
    } else {  
        return -1;  
    }  
} 

int str2Num16(const char* str)
{
  return (str[i+1] == '\0') ? HexChar2Dec(str[i]) : HexChar2Dec(str[i])*16+HexChar2Dec(str[i+1]);
}
void Parse()
{	
         char hexstr[] = "1A023b4d5c6f9";
	int len = (strlen(hexstr)%2 == 0) ? strlen(hexstr)/2 : (strlen(hexstr)/2+1);
	unsigned char hex[128] = {0};
	for (int i = 0; i < len; ++i)
	{
		int idx = i*2;
		hex[i] = str2Num16(hexstr+idx);
	}
}

更正一下 int str2Num16(const char* str) { return (str[1] == '\0') ? HexChar2Dec(str[0]) : HexChar2Dec(str[0])*16+HexChar2Dec(str[1]); }

[阿先森]

http://download.csdn.net/detail/allenemo/6487471