修正一个BUG

[Mirror然]

原帖出处 ： http://bbs.csdn.net/topics/270018720

分拆列值

原著：邹建
改编：爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开) 2007-12-16 广东深圳

有表tb, 如下:
id value
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
欲按id,分拆value列, 分拆后结果如下:
id value
----------- --------
1 aa
1 bb
2 aaa
2 bbb
2 ccc

1. 旧的解决方法(sql server 2000)
SELECT TOP 8000 id = IDENTITY(int, 1, 1) INTO # FROM syscolumns a, syscolumns b

SELECT A.id, SUBSTRING(A.[values], B.id, CHARINDEX(',', A.[values] + ',', B.id) - B.id)
FROM tb A, # B
WHERE SUBSTRING(',' + A.[values], B.id, 1) = ','

DROP TABLE #

2. 新的解决方法(sql server 2005)

create table tb(id int,value varchar(30))
insert into tb values(1,'aa,bb')
insert into tb values(2,'aaa,bbb,ccc')
go
SELECT A.id, B.value
FROM(
SELECT id, [value] = CONVERT(xml,'<root><v>' + REPLACE([value], ',', '</v><v>') + '</v></root>') FROM tb
)A
OUTER APPLY(
SELECT value = N.v.value('.', 'varchar(100)') FROM A.[value].nodes('/root/v') N(v)
)B

DROP TABLE tb

/*
id value
----------- ------------------------------
1 aa
1 bb
2 aaa
2 bbb
2 ccc

[Mirror然]

create table tb(id int,value varchar(30))
insert into tb values(1,'a&a,b&b')

原方法通过 新方法错误

[叶子]

新方法我也用过，没有错误呀

[叶子]

先DROP TABLE tb 然后再执行新方法，估计是你的表已经存在了。

[叶子]

if object_id('[tb]') is not null drop table [tb]
go
create table tb(id int,value varchar(30))
insert into tb values(1,'aa,bb')
insert into tb values(2,'aaa,bbb,ccc')
go
SELECT A.id, B.value
FROM(
    SELECT id, [value] = CONVERT(xml,'<root><v>' + REPLACE([value], ',', '</v><v>') + '</v></root>') FROM tb
)A
OUTER APPLY(
    SELECT value = N.v.value('.', 'varchar(100)') FROM A.[value].nodes('/root/v') N(v)
)B

DROP TABLE tb

[Mr_Nice]

没啥问题啊！

SELECT @@VERSION

/*Microsoft SQL Server 2008 R2 (SP1) - 10.50.2500.0 (X64)   
Jun 17 2011 00:54:03   Copyright (c) Microsoft Corporation  Enterprise Edition (64-bit) on Windows NT 6.1 <X64>
 (Build 7601: Service Pack 1) (Hypervisor) */

create table tb(id int,value varchar(30))
insert into tb values(1,'aa,bb')
insert into tb values(2,'aaa,bbb,ccc')
go

SELECT A.id, B.value
FROM(
    SELECT id, [value] = CONVERT(xml,'<root><v>' + REPLACE([value], ',', '</v><v>') + '</v></root>') FROM tb
)A
OUTER APPLY(
    SELECT value = N.v.value('.', 'varchar(100)') FROM A.[value].nodes('/root/v') N(V) 
)B

/*
id	value
1	aa
1	bb
2	aaa
2	bbb
2	ccc*/

[Mirror然]

引用 4 楼 maco_wang 的回复:

if object_id('[tb]') is not null drop table [tb]
go
create table tb(id int,value varchar(30))
insert into tb values(1,'aa,bb')
insert into tb values(2,'aaa,bbb,ccc')
go
SELECT A.id, B.value
FROM(
    SELECT id, [value] = CONVERT(xml,'<root><v>' + REPLACE([value], ',', '</v><v>') + '</v></root>') FROM tb
)A
OUTER APPLY(
    SELECT value = N.v.value('.', 'varchar(100)') FROM A.[value].nodes('/root/v') N(v)
)B

DROP TABLE tb

表数据 我跟帖已经修改了

[Mirror然]

insert into tb values(1,'a&a,b&b')

[叶子]

引用 7 楼 dr592112441 的回复:

insert into tb values(1,'a&a,b&b')

&的问题，替换掉就ok了。

if object_id('[tb]') is not null drop table [tb]
go
create table tb(id int,value varchar(30))
insert into tb values(1,'a&a,b&b')

go
declare @sign varchar(36) set @sign=newid()
declare @t table(id int,value varchar(400))

insert into @t select id,replace(value,'&',@sign) from tb
select a.id, replace(b.value,@sign,'&') as value
from(
    select id, [value] = convert(xml,'<root><v>' + replace([value], ',', '</v><v>') + '</v></root>') from @t
)a
outer apply(
    select value = n.v.value('.', 'varchar(100)') from a.[value].nodes('/root/v') n(v)
)b

drop table tb
/*
id          value
----------- ---------
1           a&a
1           b&b
*/

[daiyueqiang2045]