未知项穷举

[ImN1]

写一个python的function(*arg) 注意是不定传入

要求
function([1,2], [3,4]) 返回[[1,3], [1,4], [2,3], [2,4]]
function([1,2], [3,4], [5,6]) 返回[[1,3,5], [1,3,6], [1,4,5], [1,4,6], [2,3,5], [2,3,6], [2,4,5], [2,4,6]]
……
就是穷举了

不需考虑容错，假定输入的都是有效整数列表，但列表个数不定，列表内数目也不定

[angel_su]

试试itertools.product(*iterables, repeat=1) Python 3.3.1 (v3.3.1:d9893d13c628, Apr 6 2013, 20:30:21) [MSC v.1600 64 bit (AMD64)] on win32 Type "copyright", "credits" or "license()" for more information. >>> from itertools import product >>> list(product([1,2], [3,4])) [(1, 3), (1, 4), (2, 3), (2, 4)] >>> list(product([1,2], [3,4], [5,6])) [(1, 3, 5), (1, 3, 6), (1, 4, 5), (1, 4, 6), (2, 3, 5), (2, 3, 6), (2, 4, 5), (2, 4, 6)] >>>

[ImN1]

奶奶的，我看过这章，居然忘了