C#中字符过滤，如何做

[taylermail]

a="1,2,3,4,5,6"
b="1,4"
我想得到c(c是将a中数字过滤掉b中数字得到的结果）
c="2,3,5,6"
小弟初学 ，请详解

[coobai]

string a="1,2,3,4,5,6";
string b = "1,4";

List<string> listA = new List<string>(a.Split(','));
List<string> listB = new List<string>(b.Split(','));

List<string> listC = listA.Except<string>(listB).ToList();

[白云任去留]

string a = "1,2,3,4,5,6";
            string b = "1,4";
            string c = string.Join(",", a.Split(',').Except(b.Split(',')));
            Console.WriteLine(c11);//2,3,5,6

[白云任去留]

Console.WriteLine(c);//2,3,5,6

[EnForGrass]

   string a = "1,2,3,4,5,6";
            string b = "1,4";
            a = string.Join(",", a.Split(',').Except(b.Split(',')).ToArray());

[饕餮123]

引用 4 楼 Chinajiyong 的回复:

   string a = "1,2,3,4,5,6";
            string b = "1,4";
            a = string.Join(",", a.Split(',').Except(b.Split(',')).ToArray());

+1

[heqianmo]

将a、b的内容都分割开来，然后找a中是否有b的元素，有的话用""替换就是

[民工阿春]

string txta = "", txtb = "", cc = "";
        txta = a.Text.Trim().Trim(',');
        txtb = b.Text.Trim().Trim(',');
        string[] pp = txtb.Split(',');
        cc = "," + txta + ",";
        for (int i = 0; i < pp.Length; i++)
        {
            if (cc.Contains("," + pp[i] + ","))
            {
                txtb = pp[i] + ",";
                txta = txta.Replace(txtb, "");
            }
        }
        c.Text = txta.ToString();

小弟不才给你回复一个！

[苍狼_2001]

private ArrayList aad() { string a = "1,2,3,4,5,6"; string b = "1,4"; string[] arra = a.Split(','); string[] arrb = b.Split(','); ArrayList newlist=new ArrayList(); foreach (string temp in arra) { if (!b.Contains(temp)) { newlist.Add(temp); } } return newlist; }

[MR00009]

引用 4 楼 Chinajiyong 的回复:

   string a = "1,2,3,4,5,6";
            string b = "1,4";
            a = string.Join(",", a.Split(',').Except(b.Split(',')).ToArray());

学到了。

[dongt1]

查找--》替换--》填到新的string[] Arr中

[智者知已应修善业]

var aaa = new string("123456789".ToArray().Except("159".ToArray()).ToArray()); 

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