(新手请教）如何用new来动态分配结构数组问题

[u011187286]

stuct snack
{
char candy_name[20];
double candy_weight;
int calorie;
}candybar[3]=
{
{"chocolate",2.5,350},
{"bar",2.0,300},
{"grist",1.5,250}
}
这样一个结构数组，现在要求是，在不声明candybar数组的前提下，用new来动态分配数组，并初使化。
请高手指点，小弟在此问题上困惑不已。
不能用其它的方法哦，只能用new来动态分配数组。

[zilaishuichina]

snack *candybar = new snack[3]; strcpy(candybar[0]->candy_name, "chocolate"); candybar[0]->candy_weight = 2.5f; candybar[0]->calorie = 350; //others

[rocktyt]

    snack* candybar = new snack [3]
    {
        {"chocolate",2.5,350},
        {"bar",2.0,300},
        {"grist",1.5,250}
    };

这个语法是标准的，但可能要对标准支持比较好的编译器才能编译通过

[u011187286]

哎，可能是我的编辑器不行，你们两个说的都通过不了。

[greensroll]

你解出来了么？

[greensroll]

我也是新手，我的是这样的。 #include <iostream> #include <cstring> struct CandyBar { char name[20]; double weight; int calories; }; int main() { using namespace std; CandyBar * ps = new CandyBar[3]; strcpy(ps[0].name, "chocolate"); ps[0].weight = 1.2; ps[0].calories = 350; strcpy(ps[1].name, "bar"); ps[1].weight = 2.5; ps[1].calories = 250; strcpy(ps[2].name, "grist"); ps[2].weight = 1.8; ps[2].calories = 200; cout << "First candy: " << ps[0].name << endl; cout << "Weight: " << ps[0].weight << endl; cout << "Clories: " << ps[0].calories << endl; cout << "Second candy: " << ps[1].name << endl; cout << "Weight: " << ps[1].weight << endl; cout << "Calories: " << ps[1].calories << endl; cout << "Third candy: " << ps[2].name << endl; cout << "Weight: " << ps[2].weight << endl; cout << "Calories: " << ps[2].calories << endl; delete [] ps; return 0; }