servlet的一些问题
ip.java
package com.claire.helloworld;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.ServletException;
import java.io.IOException;
import java.io.PrintWriter;
public class ip extends HttpServlet {
private static final long serialVersionUID = 1L;
public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
response.setContentType("text/html; charset=gbk");
String a=request.getParameter("ip");
PrintWriter out = response.getWriter();
out.println("<form action=http://www.youdao.com/smartresult-xml/search.s?type=ip&q=><input type='text'name='q' id='ip' >");
out.println("<input type='submit' value='搜寻' id='tt'></form>");
}
public void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
doGet( request, response);
}
}
web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
<display-name>haha</display-name>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
<welcome-file>index.htm</welcome-file>
<welcome-file>index.jsp</welcome-file>
<welcome-file>default.html</welcome-file>
<welcome-file>default.htm</welcome-file>
<welcome-file>default.jsp</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>ip</servlet-name>
<servlet-class>com.claire.helloworld.ip</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>ip</servlet-name>
<url-pattern>/ip</url-pattern>
</servlet-mapping>
</web-app>
在ip.java中的输出的out.println("<form action=http://www.youdao.com/smartresult-xml/search.s?type=ip&q=><input type='text'name='q' id='ip' >");里面.点击提交的时候网站地址不对,type=ip&这几个不见了...该怎么弄.水平有限,学校实训的...找了好久找不到.求大虾...