http接口，报空指针，请教大虾

E_Java 2013-07-01 05:02:52

项目中要做一个发短信的功能，客户给了一个http接口url，一开始以为直接这样用BufferedReader in = new BufferedReader(new InputStreamReader(url.openStream())); 后来那个开发接口的公司说不能这样使用，也不能直接在浏览器窗口中输入url的请求：因为他们后台是这么处理的：

String result = "";

		request.setCharacterEncoding("GBK");

		BufferedReader br = request.getReader();

		String line = br.readLine();

		String[] params = line.split("&");

		Map<String,Object> param = new HashMap<String,Object>();

		for(String s : params){

			String[] keyAndValue = s.split("=");

			String key = keyAndValue[0];

			String value = keyAndValue[1];

			if(key.equals("SMSContent") || key.equals("DestMobile")) {

				value = URLDecoder.decode(value,"GBK");

			}

			param.put(key, value);

			if(!isOpen)System.out.println(key+":"+value);

		}

		if(!isOpen)System.out.println("");

		String BizType = param.get("BizType").toString();

		if(BizType.equals("01")){

			result = smsWordService.senMsgServiceAPI(param);

		}else if(BizType.equals("02")){

			System.out.println("已发短信查询");

		}else if(BizType.equals("03")){

			System.out.println("上行短信查询");

		}

后来httpClient.executeMethod(getMethod);
byte[] responseBody = getMethod.getResponseBody();
strHtml = new String(responseBody);
还是报空指针的错误，他们说给的url是正确的，是在不知道怎么写了

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xxjxxmxhlr 2013-07-02

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String inputParam = "BizType=01&LoginName=stjbpt&Password=st7023"; URL url = null; HttpURLConnection httpConn = null; OutputStream output = null; OutputStreamWriter outr = null; url = new URL("http://10.32.10.190/sms/SMSOutServlet"); //通过接口建立你的链接 httpConn = (HttpURLConnection) url.openConnection(); //这都不用你管了，都是些提交方式的写法，不过你最好确认一下是不是POST HttpURLConnection.setFollowRedirects(true); httpConn.setDoOutput(true); httpConn.setRequestMethod("POST"); httpConn.setRequestProperty("Content-Type", "text/xml"); httpConn.connect(); //获取输出流 output = httpConn.getOutputStream(); //套接 outr = new OutputStreamWriter(output); // 写入请求参数 outr.write(inputParam.toString().toCharArray(), 0, inputParam .toString().length()); outr.flush(); outr.close(); 这样穿过去是没啥问题的，但你说的为空我很在意是他们获取不到还是你获取不到呢

tubage408 2013-07-02

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URL url = new URL("http://127.0.0.1:8080/abc/index.jsp"); HttpURLConnection connection = (HttpURLConnection)url.openConnection(); connection.setDoOutput(true); connection.setUseCaches(false); //connection.setChunkedStreamingMode(0); connection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded"); connection.setRequestMethod("POST"); connection.connect(); //System.out.println(connection.getResponseCode()); String params = "userName=123&pwd=456"; OutputStream os = new BufferedOutputStream(connection.getOutputStream()); os.write(params.getBytes()); os.flush(); os.close(); connection.getResponseCode(); connection.disconnect();

E_Java 2013-07-02

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引用 7 楼 rui888 的回复:

他们的地址是 10.32.10.190，和你的不在同一服务器？他们为什么不搞个webservice 啊，搞得那么复杂。等大牛。

不在同一个服务器

tony4geek 2013-07-02

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他们的地址是 10.32.10.190，和你的不在同一服务器？他们为什么不搞个webservice 啊，搞得那么复杂。等大牛。

E_Java 2013-07-02

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引用 10 楼 xxjxxmxhlr 的回复:

String inputParam = "BizType=01&LoginName=stjbpt&Password=st7023"; URL url = null; HttpURLConnection httpConn = null; OutputStream output = null; OutputStreamWriter outr = null; url = new URL("http://10.32.10.190/sms/SMSOutServlet"); //通过接口建立你的链接 httpConn = (HttpURLConnection) url.openConnection(); //这都不用你管了，都是些提交方式的写法，不过你最好确认一下是不是POST HttpURLConnection.setFollowRedirects(true); httpConn.setDoOutput(true); httpConn.setRequestMethod("POST"); httpConn.setRequestProperty("Content-Type", "text/xml"); httpConn.connect(); //获取输出流 output = httpConn.getOutputStream(); //套接 outr = new OutputStreamWriter(output); // 写入请求参数 outr.write(inputParam.toString().toCharArray(), 0, inputParam .toString().length()); outr.flush(); outr.close(); 这样穿过去是没啥问题的，但你说的为空我很在意是他们获取不到还是你获取不到呢

太感谢了，我按照你的方法成功了。之前他们那边报空指针是因为有一段小乱码

E_Java 2013-07-01

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引用 3 楼 rui888 的回复:

关于request.getReader()

我把提交方式改为multipart/form-data还是不行啊，他们说参数不放在url后面，放在输入流里，不知道该怎么放

strb.append("http://127.0.0.1:8080/PoliceProtectionSystem/sms?BizType=01&LoginName=stjbpt&Password=st7023");
		//strb.append("http://10.32.10.190/sms/SMSOutServlet?BizType=01&LoginName=stjbpt&Password=st7023");
		strb.append("&DestMobile=").append(mobile);
		strb.append("&SMSContent=").append(content);
		try {
			httpconn = (HttpURLConnection) new URL(strb.toString()).openConnection(); 
			httpconn.setConnectTimeout(60000); 
			httpconn.setDoOutput(true); 
			httpconn.setRequestMethod("POST");
			httpconn.setUseCaches(false);
			httpconn.setInstanceFollowRedirects(true);
			httpconn.setRequestProperty("Content-Type", "multipart/form-data");
			httpconn.connect();
		    
		    ByteArrayOutputStream bout = new ByteArrayOutputStream();

		    out = new DataOutputStream(httpconn.getOutputStream());
		    out.write(bout.toByteArray());
			InputStream in = new BufferedInputStream(httpconn.getInputStream()); 
			rd = new InputStreamReader(in,"UTF-8"); 
			int c = 0; 
			StringBuilder sb = new StringBuilder();
			while ((c = rd.read()) != -1) { 
				sb.append((char) c); 
			} 
			in.close(); 
			strHtml = sb.toString();

E_Java 2013-07-01