27,579
社区成员
发帖
与我相关
我的任务
分享
declare @s nvarchar(4000) set @s=''Select @s=@s+','+quotename([日期])+'=max(case when [日期]='+quotename([日期],'''')+' then [数量] else 0 end)'from [A] group by [日期] exec('select [品号]'+@s+' from A group by [品号]')
if object_id('[TESTKC]') is not null drop table [TESTKC]
go
CREATE TABLE [dbo].[TESTKC](
[FID] [int] IDENTITY(1,1) NOT NULL,
[LA001] [nvarchar](20) NULL,
[LA004] [nvarchar](10) NULL,
[JSL] [numeric](15, 6) NULL)
insert [TESTKC]
select 1001,'06-08',10
union all
select 1001,'06-09',11
union all
select 1002,'07-07',1
union all
select 1002,'07-08',3
Declare @PivotSQL NVARCHAR(MAX)
SET @PivotSQL = N' SELECT LA001,[06-08],[06-09],[07-07],[07-08]
FROM TESTKC
pivot (sum([JSL]) FOR [LA004] IN ([06-08],[06-09],[07-07],[07-08]) ) AS BB '
execute sp_executesql @PivotSQL
查询出来的结果如下:
LA001 06-08 06-09 07-07 07-08
1001 10.000000 NULL NULL NULL
1001 NULL 11.000000 NULL NULL
1002 NULL NULL 1.000000 NULL
1002 NULL NULL NULL 3.000000
如何修改代码,使其查询的如果变成下面的结果:
LA001 06-08 06-09 07-07 07-08
1001 10.000000 11 NULL NULL
1002 NULL NULL 1.000000 3
DROP TABLE #tb
create table #tb([品号] int,[日期] varchar(5),[数量] int)
insert #tb
select 1001,'06-08',11 union all
select 1001,'06-09',12 union all
select 1001,'06-10',13 union all
select 1001,'06-11',14 union all
select 1001,'06-12',15
DECLARE @sql NVARCHAR(MAX), @colList NVARCHAR(MAX)
SET @colList = STUFF((SELECT ','+QUOTENAME([日期]) FROM #tb GROUP BY [日期] ORDER BY [日期] FOR XML PATH('')),1,1,'')
SET @sql = N'
select * from #tb a
pivot
(max([数量]) for [日期] in('+ @colList +')) b
'
EXEC(@sql)
/*
品号 06-08 06-09 06-10 06-11 06-12
1001 11 12 13 14 15
*/
declare @tbA table([品号] varchar(5),[日期] varchar(5),[数量] int)
insert into @tbA
select '1001','06-08',11 union all
select '1001','06-09',12 union all
select '1001','06-10',13 union all
select '1001','06-11',14 union all
select '1001','06-12',15 union all
select '1001','06-13',16
select [品号],
sum(case when [日期]='06-08' then [数量] else 0 end) as [06-08],
sum(case when [日期]='06-09' then [数量] else 0 end) as [06-09],
sum(case when [日期]='06-10' then [数量] else 0 end) as [06-10],
sum(case when [日期]='06-11' then [数量] else 0 end) as [06-11],
sum(case when [日期]='06-12' then [数量] else 0 end) as [06-12],
sum(case when [日期]='06-13' then [数量] else 0 end) as [06-13]
from @tbA
group by [品号]
(6 行受影响)
品号 06-08 06-09 06-10 06-11 06-12 06-13
----- ----------- ----------- ----------- ----------- ----------- -----------
1001 11 12 13 14 15 16
(1 行受影响)
CREATE TABLE #MyTable(
ID int
, time VARCHAR(10)
, count INT
)
INSERT INTO #MyTable
SELECT 1001, '06-08', 11
UNION
SELECT 1001, '06-09', 12
UNION
SELECT 1001, '06-10', 13
UNION
SELECT 1001, '06-11', 14
UNION
SELECT 1001, '06-12', 15
UNION
SELECT 1001, '06-13', 16
DECLARE @Sql VARCHAR(MAX)
SELECT @Sql=ISNULL(@Sql+',','')+'['+time+']' FROM #MyTable GROUP BY time
SELECT @Sql='SELECT *
FROM #MyTable a
PIVOT(MAX(count) FOR time IN('+@Sql+')) p '
EXEC(@Sql)
DROP TABLE #MyTable
----------------------------------------------------------------
-- Author :DBA_Huangzj(發糞塗牆)
-- Date :2013-08-09 14:40:54
-- Version:
-- Microsoft SQL Server 2014 (CTP1) - 11.0.9120.5 (X64)
-- Jun 10 2013 20:09:10
-- Copyright (c) Microsoft Corporation
-- Enterprise Evaluation Edition (64-bit) on Windows NT 6.2 <X64> (Build 9200: ) (Hypervisor)
--
----------------------------------------------------------------
--> 测试数据:[A]
if object_id('[A]') is not null drop table [A]
go
create table [A]([品号] int,[日期] varchar(5),[数量] int)
insert [A]
select 1001,'06-08',11 union all
select 1001,'06-09',12 union all
select 1001,'06-10',13 union all
select 1001,'06-11',14 union all
select 1001,'06-12',15
--------------开始查询--------------------------
declare @s nvarchar(4000)
set @s=''
Select @s=@s+','+quotename([日期])+'=max(case when [日期]='+quotename([日期],'''')+' then [数量] else 0 end)'
from [A] group by [日期]
exec('select [品号]'+@s+' from A group by [品号]')
----------------结果----------------------------
/*
品号 06-08 06-09 06-10 06-11 06-12
----------- ----------- ----------- ----------- ----------- -----------
1001 11 12 13 14 15
*/
select [品号],
sum(case when [日期]='06-08' then [数量] else 0 end) as [06-08],
sum(case when [日期]='06-09' then [数量] else 0 end) as [06-09],
sum(case when [日期]='06-10' then [数量] else 0 end) as [06-10],
sum(case when [日期]='06-11' then [数量] else 0 end) as [06-11],
sum(case when [日期]='06-12' then [数量] else 0 end) as [06-12],
sum(case when [日期]='06-13' then [数量] else 0 end) as [06-13]
from tbA
group by [品号]