如何在$.ajax 的data里面传json格式数据

qinzhenyuqzy 2013-08-18 05:17:23

问题一
jsondata={"Participant":[{"Name_1":"1","Position_1":"1","Tel_1":"1","Mobile_1":"1","Ohter_1":"1"},{"Name_2":"1","Position_2":"1","Tel_2":"2","Mobile_2":"2","Ohter_2":"2"}]}

$.ajax({
type: "POST",
contentType: "application/json;charset=utf-8",
url: "ApplyEdit.aspx/SaveParticipant",
data: 这里该怎么写,
dataType: "json",
complete: function () { },
success: function (result) {
},
error: function (result, status) { }
});
谁能告诉我这个 data:这里该如何写，我要把jsondata传到后台去

问题二
平时用的时候我有时候这么写就可以 data:{"name":name,"sex":sex},
有点时候又必须要这样写才行才能传值成功 data:"{\"name\":\""+name+"\",\"sex\":\""+sex+"\"}",
一直不明白为什么，望各位大大帮忙解释下，不胜感激

...全文

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qinzhenyuqzy 2013-08-20

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谢谢各位，5楼的比较符合我的要求

txhs 2013-08-19

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可否共享一个工程，学习一下子

tony4geek 2013-08-18

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用&符号链接成字符串后台接受方法不错。同意楼上。

ftiger 2013-08-18

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好吧，小贩思路应当比较正确


	var jsondata={"Participant":[{"Name_1":"1","Position_1":"1","Tel_1":"1","Mobile_1":"1","Ohter_1":"1"},{"Name_2":"1","Position_2":"1","Tel_2":"2","Mobile_2":"2","Ohter_2":"2"}]} ;
	
	var exdata= jQuery.extend({}, jsondata.Participant[0], jsondata.Participant[1]);
	console.log(exdata);
	
	$.ajax({
                url: "/tt.jsp",
                type: "GET",
                data:exdata,
                beforeSend: function(){
                    
                },
                success: function(d){
                   
                }
            });

街头小贩 2013-08-18

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			var jsondata={"Participant":[{"Name_1":"1","Position_1":"1","Tel_1":"1","Mobile_1":"1","Ohter_1":"1"},{"Name_2":"1","Position_2":"1","Tel_2":"2","Mobile_2":"2","Ohter_2":"2"}]} ;

			var dataString="";

  			for(var i=0; i<jsondata.Participant.length; i++){

    			for(var e in jsondata.Participant[i]){

      				dataString +=  e +"="+ jsondata.Participant[i][e] + "&" ;

    			}

  			}

			$.ajax({

				url: "/first.php",

				type: "GET",

				data: dataString.substring(0,dataString.length-1),

				beforeSend: function(){

					$('#btn').attr({'disabled':'true','value':'send data'});

				},

				success: function(d){

					$('input[name=onC]').val(d);

				}

			});

ftiger 2013-08-18

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jQuery　没有封装 json对象到json字符串的操作，你要在网上找一个这样的函数，然后 date:{"Participant":转换后的值} 随便找的转换函数，没仔细测试过

var O2String = function (O) {
        //return JSON.stringify(jsonobj);

        var S = [];
        var J = "";
        if (Object.prototype.toString.apply(O) === '[object Array]') {
            for (var i = 0; i < O.length; i++)
                S.push(O2String(O[i]));
            J = '[' + S.join(',') + ']';
        }
        else if (Object.prototype.toString.apply(O) === '[object Date]') {
            J = "new Date(" + O.getTime() + ")";
        }
        else if (Object.prototype.toString.apply(O) === '[object RegExp]' || Object.prototype.toString.apply(O) === '[object Function]') {
            J = O.toString();
        }
        else if (Object.prototype.toString.apply(O) === '[object Object]') {
            for (var i in O) {
                O[i] = typeof (O[i]) == 'string' ? '"' + O[i] + '"' : (typeof (O[i]) === 'object' ? O2String(O[i]) : O[i]);
                S.push(i + ':' + O[i]);
            }
            J = '{' + S.join(',') + '}';
        }

        return J;
	};

斯洛文尼亚旅游 2013-08-18

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将json对象转对对应的json格式的字符串就行了，下载：json2.js导入页面中

<script src="http://www.coding123.net/rardownload/20130106/20130106170832648.js"></script>
<script>
var jsondata={"Participant":[{"Name_1":"1","Position_1":"1","Tel_1":"1","Mobile_1":"1","Ohter_1":"1"},{"Name_2":"1","Position_2":"1","Tel_2":"2","Mobile_2":"2","Ohter_2":"2"}]} 
$.ajax({
                type: "POST",
                contentType: "application/json;charset=utf-8",
                url: "ApplyEdit.aspx/SaveParticipant",
                data: JSON.stringify(jsondata),//////////////////////
                dataType: "json",
                complete: function () { },
                success: function (result) {
                },
                error: function (result, status) { }
            });
</script>

传递json对象jquery会帮你转换为键值对的格式，就是xx=xx&xxxx=xxxxx... 有些时候调用webservice的方法，需要json格式的字符串，所以不能传递json对象，而是json格式的字符串，所以要传递字符串参考：jQuery调用WebService返回JSON数据

qinzhenyuqzy 2013-08-18