能否用改成lambda表达式的形式？

[wg5945]

int[] myStage = {4,4,3,3,4,4,3,3};
const int pastDays = 10;
int endDay = 0;
int stage = 0;

for (int offset = 0; offset < myStage.Length; offset++)
{
    int startDay = endDay;
    endDay = startDay + myStage[offset];
    if (pastDays <= startDay || pastDays > endDay) continue;
    stage = offset;
    break;
}
Console.Write(stage);

上面的代码能否改成lambda表达式的形式，能不能简便一些~~

[wg5945]

没有大神莅临指导一下么~~ 想学习一下lambda式的写法~~

[q107770540]

	int[] myStage = {4,4,3,3,4,4,3,3};
	const int pastDays = 10;
    int startDay =0;
    int stage =myStage.Select((x,i)=>new {x,i})
					  .Aggregate((x,y)=>
								{
									startDay+=x.x;
								    return startDay>=pastDays?x:y;
								}).i;
	Console.WriteLine(stage);

[claymore1114]

            int[] myStage = { 4, 4, 1, 3, 4, 4, 3, 3 };
            const int pastDays = 10;
            int endDay = 0;

            int stage = Array.FindIndex(myStage, o =>
            {
                int startDay = endDay;
                endDay = startDay + o;

                return (startDay < pastDays && pastDays <= endDay);
            });

[wg5945]

引用 3 楼 claymore1114 的回复:

            int[] myStage = { 4, 4, 1, 3, 4, 4, 3, 3 };
            const int pastDays = 10;
            int endDay = 0;

            int stage = Array.FindIndex(myStage, o =>
            {
                int startDay = endDay;
                endDay = startDay + o;

                return (startDay < pastDays && pastDays <= endDay);
            });

谢谢~~

[wg5945]

引用 2 楼 q107770540 的回复:

	int[] myStage = {4,4,3,3,4,4,3,3};
	const int pastDays = 10;
    int startDay =0;
    int stage =myStage.Select((x,i)=>new {x,i})
					  .Aggregate((x,y)=>
								{
									startDay+=x.x;
								    return startDay>=pastDays?x:y;
								}).i;
	Console.WriteLine(stage);

其实我发这个帖子，就是想看看你回复的一些很牛逼的写法~~

[threenewbee]

int[] myStage = { 4, 4, 3, 3, 4, 4, 3, 3 }; const int pastDays = 10; int sum = 0; int stage = myStage.TakeWhile(x => (sum += x) < pastDays).Count(); Console.Write(stage);

[threenewbee]

来迟了。。。

[q107770540]

总感觉目前的代码还不够牛X,期待更牛X的代码出现~ 还有个思路，就是将判断的逻辑封装成扩展方法，直接 int stage = myStage.扩展方法名(10) 获取即可

[q107770540]

引用 6 楼 caozhy 的回复:

int[] myStage = { 4, 4, 3, 3, 4, 4, 3, 3 }; const int pastDays = 10; int sum = 0; int stage = myStage.TakeWhile(x => (sum += x) < pastDays).Count(); Console.Write(stage);

TakeWhile在此处用的巧妙~

[threenewbee]

引用 9 楼 q107770540 的回复:

[quote=引用 6 楼 caozhy 的回复:] int[] myStage = { 4, 4, 3, 3, 4, 4, 3, 3 }; const int pastDays = 10; int sum = 0; int stage = myStage.TakeWhile(x => (sum += x) < pastDays).Count(); Console.Write(stage);

TakeWhile在此处用的巧妙~[/quote] 听到糖糖夸我，比得了分还高兴。