正则表达式拆分成数组

huiyaxiong 2013-10-22 02:48:46

string a="PT<0101,Field>*PT<010203,MonthSum>+345*(PT<0101,Field>+PT<01091,Field>)"

拆分成如下数组：PT<0101,Field>
PT<010203,MonthSum>
PT<0101,Field>
PT<01091,Field>

大虾些只有40分

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q107770540 2013-10-22

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引用 2 楼 huiyaxiong 的回复:

"0101,Field" "010203,MonthSum" "0101,Field" "01091,Field" 大虾如果拆分成这种呢

string[] result = Regex.Matches(a, @"PT\<(\d+\,\w+?)\>").Cast<Match>().Select(x => x.Groups[1].Value).ToArray();

骑着蜗牛去爬山 2013-10-22

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string[] result = Regex.Matches(a, @"(?<=PT<)[^<>]+(?=>)").OfType<Match>().Select(x => x.Value).ToArray();

huiyaxiong 2013-10-22

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引用 1 楼 caozhy 的回复:

string a = "PT<0101,Field>*PT<010203,MonthSum>+345*(PT<0101,Field>+PT<01091,Field>)"; string[] result = Regex.Matches(a, @"PT\<\d+\,\w+?\>").Cast<Match>().Select(x => x.Value).ToArray();

大虾如果拆分成这种呢 "0101,Field" "010203,MonthSum" "0101,Field" "01091,Field"

huiyaxiong 2013-10-22

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"0101,Field" "010203,MonthSum" "0101,Field" "01091,Field" 大虾如果拆分成这种呢

threenewbee 2013-10-22

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string a = "PT<0101,Field>*PT<010203,MonthSum>+345*(PT<0101,Field>+PT<01091,Field>)"; string[] result = Regex.Matches(a, @"PT\<\d+\,\w+?\>").Cast<Match>().Select(x => x.Value).ToArray();