server client

[u010861420]

我想要做客戶端後傳訊息
我想要多客戶
我開兩個Client沒辦法
Server一次只能接收和傳送一邊的資料

可能是因為我的傳送和接收不能同時進行
是缺什麼??

#!/usr/bin/env python
# -*- coding: cp950 -*-

import socket
server= ''
port = 12000
s=socket.socket(socket.AF_INET,socket.SOCK_STREAM)
s.bind((server,port))
s.listen(300)

a=0

while True:
    client,addr=s.accept()
    print('IP:',addr)
    if a==0:data =client.recv(1024)
    print("client say:",repr(data))
    a=1
    if a==1:text=raw_input("key number:")
    client.send(text) 
    a=0

#!/usr/bin/env python
# -*- coding: cp950 -*-

import socket
server= '127.0.0.1'
port = 12000

s=socket.socket(socket.AF_INET,socket.SOCK_STREAM)

s.connect((server,port))
a=1

while True:
    if a==1:text=raw_input("key number:")
    s.send(text) 
    a=0
    if a==0:data=s.recv(1024)
    print("server say:",repr(data))
    a=1 

[angel_su]

简单的可以试试SocketServer模块，最好研读一下该模块的py代码...

[u010861420]

可以連多個....但傳訊息還是只能一對一.... server

#!/usr/bin/env python
import socket
import sys
import threading
import time

server= ''
port = 12000
s=socket.socket(socket.AF_INET,socket.SOCK_STREAM)

try:
    s.bind((server,port))
except socket.error as msg:
    print 'Bind failed. Error Code : ' + str(msg[0]) + ' Message ' + msg[1]
    sys.exit() 
s.listen(300)

def recv(sec, str):
    while 1:
		data =client.recv(1024)
		print("\n")
		print(str,repr(data))
		print("send:")
def send(sec, str):
    while 1:
		text=raw_input(str)
		client.send(text)
def connect(sec, str):
    while 1:
		client, addr = s.accept()
		print 'Connected with' 

threads = []
t = threading.Thread(target=recv, args=(1, "client"))
threads.append(t)
t = threading.Thread(target=send, args=(1, "send:\n"))
threads.append(t)
t = threading.Thread(target=connect, args=(1, "send:\n"))
threads.append(t)
while 1:
		client, addr = s.accept()
		print 'Connected with ' + addr[0] + ':' + str(addr[1])
		threads[0].start()
		threads[1].start()
		threads[2].start()
		threads[0].join()
		threads[1].join()
		threads[2].join()

client

#!/usr/bin/env python
 
import socket
import threading
import time
import sys

server= '127.0.0.1'
port = 12000

def recv(sec, str):
    while 1:
		data =s.recv(1024)
		print("\n")
		print(str,repr(data))
		print("send:")
def send(sec, str):
    while 1:
		text=raw_input(str)
		s.send(text)
s=socket.socket(socket.AF_INET,socket.SOCK_STREAM)
threads = []
t = threading.Thread(target=recv, args=(1, "server"))
threads.append(t)
t = threading.Thread(target=send, args=(1, "send:\n"))
threads.append(t)
try:
    s.connect((server,port))
    threads[0].start()
    threads[1].start()
    threads[0].join()
    threads[1].join()
except socket.error as msg:
    print 'Bind failed. Error Code : ' + str(msg[0]) + ' Message ' + msg[1]
    sys.exit() 

[u010861420]

能介紹書或是哪個網站說很清楚的嗎? http://docs.python.org/2/library/socketserver.html 這個網站看了很久還是不了解

[angel_su]

你主要问题是没注意accept，recv，send都是阻塞式调用，服务器卡在一个点上没法同时响应多个客户端，后面虽然改为多线程，但客户端的连接却晾在一边，基本上都乱套了。试试上述手册里第一个例子当服务器，你顶楼第一次自己写的客户端，起几个去连接，应该没问题，然后研究源码(Pythonxx/Lib/SocketServer.py)，看人家怎么写的...

[angel_su]

貌似对socket没理解清楚，即使起线程强兜在一起也不是想要的结果。前面说过了，你先试试SocketServer模块，有兴趣自己写就先研读它的代码，就一个py文件代码不长，认真看...