如何用jquery取道下面的值

[chenqishanghai]

如何取到div class="a"下面<div style="display: block; "><span class="num">的值2500

<div class="a">
<div style="display: block; ">
<table>
<tbody><tr>

<div class="title">
<span class="num">2500</span>
</div>
</div>
</td>
</tr>
</tbody></table>
</div>


<div style="display: none; ">
<table>
<tbody><tr>

<div class="title">
<span class="num">2700</span>
</div>
</div>
</td>
</tr>
</tbody></table>
</div>


</div>

[bobbyworm]

你这个html结构不规范，<div style="display: block; ">和<table>标签交叉了

[chenqishanghai]

改成这样如何?请教一下如何取到 <div class="a"> <div style="display: block; "> <div class="title"> <span class="num">2500</span> </div> </div> </div> <div style="display: none; "> <div class="title"> <span class="num">2700</span> </div> </div> </div> </div>

[bobbyworm]

后面仍然多了两个</div>，不过就算了，整理一下格式：

<div class="a">
	<div style="display: block; ">
		<div class="title">
			<span class="num">2500</span>
		</div>
	</div>
</div>

<div style="display: none; ">
	<div class="title">
		<span class="num">2700</span>
	</div>
</div>

可以这样取：

$('div.a>div:visible .num').text()
//或者
$('div.a>[style*="block"] .num').text()

[泡泡鱼_]

换个角度去构造DOM,类似于这样加多个虚拟的class,是不是简单多了呢?

<div class="a"> 
    <div style="display: block; "> 
        <div class="title"> 
            <span class="num show">2500</span> 
        </div> 
    </div> 
</div> 
  
<div style="display: none; "> 
    <div class="title"> 
        <span class="num hide">2700</span> 
    </div> 
</div>