xml递归解析

2014-01-27 04:10:53 225 阅读 AI 写同款 · GEO 优化AI 选题数据监测一键分发 ›

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<?xml version="1.0" encoding="UTF-8"?>

<resources>

    <resource name="level1" >



        <resource name="level2" >

            <resource name="level3" >

            </resource>

        </resource>



    </resource>

    <resource name="text1" >

</resources>

遍历这个xml 要得到如下效果：



public class Xml2 {



	/**

	 * @param args

	 */

	public static void main(String[] args) {

		// TODO Auto-generated method stub 10jq

		Node root=new Node();

		root.text="";

		root.children=new ArrayList<Node>();

		Node level1=new Node();

		level1.text="level1";

		level1.children=new ArrayList<Node>();

		Node level2=new Node();

		level2.text="level2";

		level2.children=new ArrayList<Node>();

		Node level3=new Node();

		level3.text="level3";

		level3.children=new ArrayList<Node>();

		

		level2.children.add(level3);

		level1.children.add(level2);

		

		Node text1=new Node();

		text1.text="level3";

		text1.children=new ArrayList<Node>();

		root.children.add(text1);

	}



}



class Node{

	public String text;

	public List children;

}

要通过遍历xml自动获得这个list

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pngg 2014-03-12

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引用 1 楼 beijinuo 的回复:

直接贴代码



import java.math.BigDecimal;
import java.util.ArrayList;
import java.util.Iterator;
import java.util.List;

import org.dom4j.Document;
import org.dom4j.DocumentException;
import org.dom4j.DocumentHelper;
import org.dom4j.Element;

import com.sun.org.apache.regexp.internal.recompile;
import com.yxd.pris.model.TVideo;

/**
 *功能说明:
 *
 *创建人: 刘飞
 *
 *创建时间:2014-1-27 下午04:58:49
 *
 *修改人             修改时间             修改描述
 *
 *
 *Copyright (c)2014 
 * 
 */
public class Node {
	private String text;
	private List children;
	public String getText() {
		return text;
	}
	public void setText(String text) {
		this.text = text;
	}
	public List getChildren() {
		return children;
	}
	public void setChildren(List children) {
		this.children = children;
	}
	public static void main(String[] args) {
		String xml = "<?xml version=\"1.0\" encoding=\"UTF-8\"?>" +
		"<resources>" +
		"<resource name=\"level1\" >" +
		"<resource name=\"level2\" >" +
		" <resource name=\"level3\" >" +
		"</resource>" +
		"</resource>" +
		"</resource>" +
		"<resource name=\"text1\" />" +
		"</resources>";
		Document doc = null;
		try {
			doc = DocumentHelper.parseText(xml);
			Element rootElt = doc.getRootElement(); // 获取根节点
			Node node = new Node();
			node.setText(rootElt.attributeValue("name"));
			node.recursiveXML(rootElt, 0, node);
		} catch (DocumentException e) {
			e.printStackTrace();
		} // 将字符串转为XML
        
	}
	
	private void recursiveXML(Element element,int next,Node node) {
		node.children = new ArrayList<Node>();
		String url ="/";
		for (int i = 0; i < next; i++) {
			url = url+"/resource";
		}
		next++;
		List list = element.selectNodes(url);
		if (list.size() > 0 ) {
			Iterator resource = element.elementIterator("resource"); //获取根节点下的子节点resource
           //遍历zone节点
           while (resource.hasNext()) {
        	   Element resourceEle = (Element) resource.next();
    		   String resourceName = resourceEle.attributeValue("name");
    		   Node childNode = new Node();
    		   childNode.setText(resourceName);
    		   node.children.add(childNode);
               recursiveXML(resourceEle,next,childNode);
           }
		}
	}
}

忘了结贴

心梦飞扬 2014-01-27

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直接贴代码



import java.math.BigDecimal;
import java.util.ArrayList;
import java.util.Iterator;
import java.util.List;

import org.dom4j.Document;
import org.dom4j.DocumentException;
import org.dom4j.DocumentHelper;
import org.dom4j.Element;

import com.sun.org.apache.regexp.internal.recompile;
import com.yxd.pris.model.TVideo;

/**
 *功能说明:
 *
 *创建人: 刘飞
 *
 *创建时间:2014-1-27 下午04:58:49
 *
 *修改人             修改时间             修改描述
 *
 *
 *Copyright (c)2014 
 * 
 */
public class Node {
	private String text;
	private List children;
	public String getText() {
		return text;
	}
	public void setText(String text) {
		this.text = text;
	}
	public List getChildren() {
		return children;
	}
	public void setChildren(List children) {
		this.children = children;
	}
	public static void main(String[] args) {
		String xml = "<?xml version=\"1.0\" encoding=\"UTF-8\"?>" +
		"<resources>" +
		"<resource name=\"level1\" >" +
		"<resource name=\"level2\" >" +
		" <resource name=\"level3\" >" +
		"</resource>" +
		"</resource>" +
		"</resource>" +
		"<resource name=\"text1\" />" +
		"</resources>";
		Document doc = null;
		try {
			doc = DocumentHelper.parseText(xml);
			Element rootElt = doc.getRootElement(); // 获取根节点
			Node node = new Node();
			node.setText(rootElt.attributeValue("name"));
			node.recursiveXML(rootElt, 0, node);
		} catch (DocumentException e) {
			e.printStackTrace();
		} // 将字符串转为XML
        
	}
	
	private void recursiveXML(Element element,int next,Node node) {
		node.children = new ArrayList<Node>();
		String url ="/";
		for (int i = 0; i < next; i++) {
			url = url+"/resource";
		}
		next++;
		List list = element.selectNodes(url);
		if (list.size() > 0 ) {
			Iterator resource = element.elementIterator("resource"); //获取根节点下的子节点resource
           //遍历zone节点
           while (resource.hasNext()) {
        	   Element resourceEle = (Element) resource.next();
    		   String resourceName = resourceEle.attributeValue("name");
    		   Node childNode = new Node();
    		   childNode.setText(resourceName);
    		   node.children.add(childNode);
               recursiveXML(resourceEle,next,childNode);
           }
		}
	}
}

xml递归解析

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