关于用时间片控制函数该如何实现啊？

[otherL]

比如有2个函数A合B执行时间都在10秒以上，按A执行1秒挂起->B执行1秒挂起，循环。
该怎么实现啊，本人编程新手，望高手说详细些！谢谢了！

[turing-complete]

以前的写的一个类似的，不是很好，仅供参考吧。

#include <condition_variable>
#include <iostream>
#include <mutex>
#include <thread>

namespace {

const size_t kRotationCount = 5;
std::mutex mtx;
bool should_turn_to_sub = true;
std::condition_variable cond;

} // namespace

void RunSubThread() {
  for (size_t i = 0; i < kRotationCount; ++i) {
    std::unique_lock<std::mutex> lock(mtx);
    cond.wait(lock, []{return should_turn_to_sub;});
    std::cout << "The sub thread is running." << std::endl;
    should_turn_to_sub = false;
    cond.notify_one();
  }
}

void RunMainThread() {
  for (size_t i = 0; i < kRotationCount; ++i) {
    std::unique_lock<std::mutex> lock(mtx);
    cond.wait(lock, []{return !should_turn_to_sub;});
    std::cout << "The main thread is running." << std::endl;
    should_turn_to_sub = true;
    cond.notify_one();
  }
}                                                                                                                                                                                              

int main(int argc, char* argv[]) {
  std::thread(RunSubThread).detach();
  RunMainThread();
}