如何获取StringBuffer中有多少个“\n”?

[宁缺爱不滥情]

StringBuffer detailBuffer = new StringBuffer();

//迭代 bbbbDTOList
for (aaaaDTO fieldDTO :bbbbDTOList) {
LifeCycle oldLifeCycle = cmd.getOldLifeCycle();
LifeCycle newLifeCycle = cmd.getNewLifeCycle();
if (null == oldLifeCycle && null == newLifeCycle ) {
continue;
} else if (null == oldLifeCycle && null != newLifeCycle ) {
detailBuffer.append(" 添加:" + newLifeCycle + "\n");
} else if (null != oldLifeCycle && null == newLifeCycle ) {
detailBuffer.append(" 删除:" + oldLifeCycle + "\n");
} else if (!oldLifeCycle .equals(newLifeCycle )) {
detailBuffer.append(" 更改:" + newLifeCycle + "\n");
}
}
StringBuffer 中最后得到的数据 中是以“\n”隔开的！
现在我想统计 StringBuffer 中有多少个 “\n” 如何 实现？？

[Defonds]

用正则去匹配出来

[vcshcn]

从头到尾比较每一个byte值

[火龙果被占用了]

detailBuffer.append(" 删除:" + oldLifeCycle + "\n"); 用于 StringBuffer ，还在用字符串拼接，有啥意思么？

[zark]

1 2 3 4 5

[tony4geek]

StringBuffer detailBuffer = new StringBuffer();
		detailBuffer.append("sdsd\ndwewe\n32323\n333332");
		Pattern p = Pattern.compile("\n");
		int i = 0;
		Matcher m = p.matcher(detailBuffer.toString());
		while (m.find()) {
			i++;
		}
		System.out.println(i);