js处理JSON数据去重（大婶快来）

[孔乙己、]

{                                                      
	"total":3,                                                      
	"rows":[                                                          
		{"code":"001","name":"北京市","qymc":"雪花啤酒","pfkmc":"雪花排气口1#"},         
		{"code":"002","name":"北京市","qymc":"雪花啤酒","pfkmc":"雪花排气口2#"},         
		{"code":"003","name":"上海市","qymc":"雪花啤酒","pfkmc":"雪花排气口2#"}
	]                                                          
}   

需求：name重复的json 只留一条，就是如果name相同就去重

[zhjdg]

	var $a ={                                                      
	    "total":3,                                                      
	    "rows":[                                                          
	        {"code":"001","name":"北京市","qymc":"雪花啤酒","pfkmc":"雪花排气口1#"},         
	        {"code":"002","name":"北京市","qymc":"雪花啤酒","pfkmc":"雪花排气口2#"},         
	        {"code":"003","name":"上海市","qymc":"雪花啤酒","pfkmc":"雪花排气口2#"}
	    ]                                                          
	}
	
	$b = {"total":0,"rows":[]};
	var tem = $a.rows;
	var len = tem.length;
	var i=0;
	var arr = [];
	for(; i<len; i++){		
		var t = tem[i];
		if(arr.indexOf(t['name']) ==-1){
			arr.push(t['name']);
			$b.rows.push(t);
			$b.total++;
		}
		
	}
	
	var newarr = $b;

[___紫菜]

IE好像不支持arr.indexOf

[sinat_25866063]

//JOSN数组去重的算法 JS var tem = $a.rows; tem.unique1 (); Array.prototype.unique1 = function () { var res = [this[0]]; for (var i = 1; i < this.length; i++) { var repeat = false; for (var j = 0; j < res.length; j++) { if (this[i].name== res[j].name) { repeat = true; break; } } if (!repeat) { res.push(this[i]); } } return res; }

[PolarisSeven]

引用 1 楼 u011461314 的回复:

	var $a ={                                                      
	    "total":3,                                                      
	    "rows":[                                                          
	        {"code":"001","name":"北京市","qymc":"雪花啤酒","pfkmc":"雪花排气口1#"},         
	        {"code":"002","name":"北京市","qymc":"雪花啤酒","pfkmc":"雪花排气口2#"},         
	        {"code":"003","name":"上海市","qymc":"雪花啤酒","pfkmc":"雪花排气口2#"}
	    ]                                                          
	}
	
	$b = {"total":0,"rows":[]};
	var tem = $a.rows;
	var len = tem.length;
	var i=0;
	var arr = [];
	for(; i<len; i++){		
		var t = tem[i];
		if(arr.indexOf(t['name']) ==-1){
			arr.push(t['name']);
			$b.rows.push(t);
			$b.total++;
		}
		
	}
	
	var newarr = $b;

感谢，对我帮助很大