c++编写一个void Reverse(string &s)函数，还要用递归，使字符串倒序。

[u014530518]

求助，谁能写个简单的给我

[测试NULL]

#include <string>
#include <iostream>

using namespace std;

void Reverse(string &s, int index)
{
    static string copy_str = string(s.length(), '\0');

    if (index == s.length())
    {
        cout << copy_str << endl;
        return;
    }
    
    copy_str[index] = s[s.length()-index-1];
    
    Reverse(s, index+1);
}
int main(void)
{
    string s = "abc";
    Reverse(s, 0);
    
    return 0;
}

[测试NULL]

#include <string>
#include <iostream>

using namespace std;

void Reverse(string &s)
{
    static string copy_str = string(s.length(), '\0');
    static int index;

    if (index == s.length())
    {
        s = string(copy_str);
        return;
    }
    
    copy_str[index] = s[s.length()-index-1];
    index++;
    
    Reverse(s);
}

int main(int argc, const char * argv[])
{
    string s = "abcdefg";
    Reverse(s);
    
    cout << s << endl;
    
    return 0;
}

[测试NULL]

额

#include <string>
#include <iostream>

using namespace std;

void Reverse(string &s)
{
    size_t len = s.length();
    static int index = 0;

    if (index <= (len/2))
    {
        char temp = s[index];
        s[index] = s[len-index-1];
        s[len-index-1] = temp;
        
        ++index;
        Reverse(s);
    }
}

int main(int argc, const char * argv[])
{
    string s = "abcdefg";
    Reverse(s);
    
    cout << s << endl;
    
    return 0;
}

[lm_whales]

void Reverse(string &s，int i,int j){ if(i>=j)return; char c = s[i]; s[i] = s[j]; s[j]=c; Reverse(++i,--j); } void Reverse(string &s){ Reverse(0,s.size()-1); } int main() { string s("abcdefg"); cout<<"Before reverse: s = "<<s<<endl; Reverse(s); cout<<"After reverse: s = "<<s<<endl; } PS : 这种事情为何要使用递归？？？

[lm_whales]

#include<string>
#include<iostream>
using namespace std;

void Reverse(string &s，int i,int j){
         if(i>=j)return;
         char c = s[i]; s[i] = s[j]; s[j]=c;
         Reverse(++i,--j);
}
void Reverse(string &s){     Reverse(0,s.size()-1); }

int main()
{
        string s("abcdefg");
        cout<<"Before reverse: s = "<<s<<endl;
        Reverse(s);
        cout<<"After reverse: s = "<<s<<endl; 
}

[buyong]

http://www.cplusplus.com/reference/algorithm/reverse/

[lm_whales]

void Reverse(string &s){ Reverse(s,0,s.size()-1); }