用for给数组赋值

[yyixin]

$tests=array(id => "910003", params => array("param1" => '', "param2" => '', "param3" => ''));

for ($i = 0; $i <= count($tests["params"]); $i++) {
   
}

如何用上述方法修改param1，param2，param3值？

[yyixin]

$i <= count($tests["params"]) 应为 $i < count($tests["params"])

[xuzuning]

$tests = array('id' => "910003", 'params' => array("param1" => '', "param2" => '', "param3" => ''));
foreach($tests["params"] as $k=>&$t) $t = $k;
print_r($tests);

Array
(
    [id] => 910003
    [params] => Array
        (
            [param1] => param1
            [param2] => param2
            [param3] => param3
        )
)

$tests = array('id' => "910003", 'params' => array("param1" => '', "param2" => '', "param3" => ''));
for($i=1; $i<=count($tests["params"]); $i++) {
  $tests["params"]['param'.$i] = $i;
}
print_r($tests);

Array
(
    [id] => 910003
    [params] => Array
        (
            [param1] => 1
            [param2] => 2
            [param3] => 3
        )
)

[yyixin]

谢谢！，如果这个参数名是没有规律的（如：param_23、paramAbc……），那有如何实现

[xuzuning]

不是给了你两个方案了吗？

[yyixin]

哦，明白了！谢谢！

[天涯过客009]

$tests=array(
'id' => "910003", 
'params' => array(
                  "param1" => '', 
                  "param2" => '', 
                  "param3" => ''
                  )
);
for ($i = 1; $i<=count($tests["params"]); $i++) {
        $tests['params']['param'.$i]=$i;
}
print_r($tests['params']);

[天涯过客009]

引用 3 楼 yyixin 的回复:

谢谢！，如果这个参数名是没有规律的（如：param_23、paramAbc……），那有如何实现

如果没有规律，只能换一种办法了