编译出现错误，求大神讲解error: functional cast expression list treated as compound expressio

[dai1992]

编译出现错误，求大神讲解error: functional cast expression list treated as compound expression
函数实现功能：输入员工的姓名，出生日期（月/日),按日期大小输出员工姓名
#include<iostream>
using namespace std;
struct Employ{
string a;
int mouth;
int day;
};
void sort(Employ e[],int n)
{
Employ temp;
for(int i=0;i<n;i++)
{ temp.a=e.a;
temp.mouth=e.mouth;
temp.day=e.day;
for(int j=i+1;j<0;j++)
{
if(temp.mouth>e[j].mouth)
{temp.mouth=e[j].mouth;
temp.day=e[j].day;
temp.a=e[j].a;
}
if(temp.mouth==e[j].mouth){
if(temp.day>e[j].day)
{
temp.a=e[j].a;
temp.day=e[j].day;
}
}
}
cout<<temp.a<<temp.mouth<<temp.day<<endl;

}
}
int main()
{
int num;
cout<<"please intput the number of employ"<<endl;
cin>>num;
Employ e_num[num];
for(int i=0;i<num;i++)
{

cout<<"please input the name of "<<i+1<<" employ "<<endl;
cin>>e_num.a;
cout<<"please input the mouth of "<<i+1<<" employ (1-12)"<<endl;
cin>>e_num.mouth;
cout<<"please input the day of "<<i+1<<" employ (1-31)"<<endl;
cin>>e_num.day;
cout<<endl;
}
void(e_num,num);
return 0;
}

[逸萌]

错误在哪行？ 最好用STL的Sort

[微型蚂蚁]

void sort(Employ e[],int n) 数组里面元素的引用 不能直接e.a 应该类似是e[0].a