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ALTER FUNCTION [dbo].insert_coord1
(@startnum INT, @startx FLOAT, @starty FLOAT, @endnum INT, @endx FLOAT, @endy FLOAT)
RETURNS FLOAT
AS
BEGIN
-- routine body goes here, e.g.
-- SELECT 'Navicat for SQL Server'
SET @startnum = 1
SET @startx = 128.384729
SET @starty = 83.845837
SET @endnum = 51
SET @endx = 139.847212
SET @endy = 85.843872
RETURN @startx -- 此处如何能返回两个值
END