java读取json格式数据

[jefft1]

{
    "status":0,
    "message":"ok",
    "results":[
        {
            "name":"重庆秦妈火锅(马仁山东路店)",
            "location":{
                "lat":31.312634,
                "lng":118.406372
            },
            "address":"弋江区马仁山东路275号（南瑞世纪联华超市向东200米）",
            "telephone":"0553-5919177",
            "uid":"d01b6bf9e9ea6f9e4d776e95",
            "detail_info":{
                "type":"cater",
                "tag":"火锅,餐饮",
                "detail_url":"http://api.map.baidu.com/place/detail?uid=d01b6bf9e9ea6f9e4d776e95&output=html&source=placeapi_v2",
                "price":"45",
                "overall_rating":4.5,
                "service_rating":2,
                "environment_rating":4.5,
                "image_num":"30",
                "groupon_num":4,
                "comment_num":"283"
            }
        }
    ]
}

在这个json格式的数据中我已经将部分数据用java代码形式进行读取出来了，可是在location和detail_info这两个部分的数据我知道应该用JSONObject来进行读取，可是我却不知道该怎么去写，下面是我写的读取除location和detail_info两个之外其它数据

    public static void main(String[] args) throws IOException {
        JSONArray jsonArray = searchLocation("芜湖");
        Iterator iteratorArray = jsonArray.iterator();
        while (iteratorArray.hasNext()) {
            JSONObject json = (JSONObject) iteratorArray.next();
            String results = json.getString("results");
            JSONArray resultArray = JSONArray.fromObject(results);
            Iterator iteratorResult = resultArray.iterator();
            while (iteratorResult.hasNext()) {
                JSONObject iteratorJson = (JSONObject) iteratorResult.next();
                System.out.println(iteratorJson.getString("name"));
                System.out.println(iteratorJson.getString("address"));
                System.out.println(iteratorJson.getString("telephone"));
                System.out.println(iteratorJson.getString("uid"));
                JSONObject json_location = (JSONObject) iteratorArray.next();
                JSONObject json_details = (JSONObject) iteratorArray.next();
                String location = json_location.getString("location");
                String details = json_details.getString("detail_info");
            }
        }
    }

接下来的该如何去写呢？求大神帮忙！

[tony4geek]

楼上的方法试试看那。

[jefft1]

楼上的方法还是不行

[别闹腰不好]

你要是不json 转成java对象 就得这么转， 你应该是哪里写的不对 。

[别闹腰不好]

public static void main(String[] args) throws IOException { JSONArray jsonArray = searchLocation("芜湖"); Iterator iteratorArray = jsonArray.iterator(); while (iteratorArray.hasNext()) { JSONObject json = (JSONObject) iteratorArray.next(); String results = json.getString("results"); JSONArray resultArray = JSONArray.fromObject(results); Iterator iteratorResult = resultArray.iterator(); while (iteratorResult.hasNext()) { JSONObject iteratorJson = (JSONObject) iteratorResult.next(); System.out.println(iteratorJson.getString("name")); System.out.println(iteratorJson.getString("address")); System.out.println(iteratorJson.getString("telephone")); System.out.println(iteratorJson.getString("uid")); String location = iteratorJson.getString("location"); String details = iteratorJson.getString("detail_info"); JSONObject location =JSONObject.fromObject(location ); JSONObject details =JSONObject.fromObject(details ); System.out.println(details .getString("environment_rating")); } } }

[snow-is-my-Love]

map里有map 该怎么遍历就怎么遍历

[别闹腰不好]

location和detail_info和上边的一样的解析 ，你都能解析一部分了 ，我想剩下的也能解析。

[别闹腰不好]

String location = json_location.getString("location"); String details = json_details.getString("detail_info"); JSONObject location =JSONObject.fromObject(location ); JSONObject details =JSONObject.fromObject(details ); details .getString("environment_rating");要说取啥就行了 。 JSONObject 就是 json字符串和javaBean的中间对象 ，