Repeater1_ItemDataBound 事件中的两个 DropDownList ，如何实现省市联动

[tiger8000]

protected void Repeater1_ItemDataBound(object sender, RepeaterItemEventArgs e)
{
if (e.Item.ItemType == ListItemType.Item || e.Item.ItemType == ListItemType.AlternatingItem)
{
DropDownList dropt1 = (DropDownList)e.Item.FindControl("DropDownList1");
DropDownList dropt2 = (DropDownList)e.Item.FindControl("DropDownList2");
//以下要如何实现 dropt1 的 dropt1 _SelectedIndexChanged ，并 让drop2 能取到drop1的值，
//实现数据绑定
}
}


正常情况 下，如果DropDownList1 和 DropDownList2 不在Repeater1_ItemDataBound 事件中，联动非常容易：

protected void DropDownList1_SelectedIndexChanged(object sender, EventArgs e)
{
//取得DropDownList1 值，实现 DropDownList2 数据绑定

}

[蝶恋花雨]

     <asp:dropdownlist id="DropDownList1 " autopostback="true" onselectedindexchanged="DropDownList1_SelectedIndexChanged" runat="server"></asp:dropdownlist>

ItemDataBound中
   if (e.Item.ItemType == ListItemType.Item||e.Item.ItemType==ListItemType.AlternatingItem||e.Item.ItemType==ListItemType.EditItem)
        {
            DropDownList myDrop = e.Item.FindControl("DropDownList1 ") as DropDownList;
            if (myDrop.Items.Count == 0)
            {
                myDrop.Items.Add(new ListItem("a", "1"));
                myDrop.Items.Add(new ListItem("b", "2"));
                myDrop.DataBind();
            }
        }

 protected void DropDownList1_SelectedIndexChanged(object sender,EventArgs e)
    {
        var selectvalue=((DropDownList)sender).SelectedIndex.ToString();//得到DropDownList1选中的值
//然后查询数据库绑定
for(int i=0;i<rp.rows.count;i++)
{
//循环遍历招待第二个DropDownList2 然后绑定
}
    }

[蝶恋花雨]

参考 http://huobazi.cnblogs.com/archive/2006/04/08/TwoDropDownListInDataGridAndBubbleEvent.html

[aspnet30]

现在还在用webform? 用原生态的html控件啊，然后通过js联动，你这种联动还需要回传服务器刷新页面

[Hertz_liu]

这玩意我觉得你还是用ajax吧