请教一下Python中将字典数组(dict)转换为固定数组(tuple)的问题

[ucdosxp]

例:
a=[{"1":"a","2":"b","3","c"},{"4":"d","5":"e","6","f"},{"7":"g","8":"h","9","i"}]
先需将a(字典型)转换成b(固定数组型)
b=(("a","b","c"),("d","e","f"),("g","h","i"))
如何快速简单的转换，最好无须用循环函数。谢谢各位了！！！

[The_Third_Wave]

>>> a=[{"1":"a","2":"b","3":"c"},{"4":"d","5":"e","6":"f"},{"7":"g","8":"h","9":"i"}] >>> for i in range(len(a)): print i 0 1 2 >>> b = [] >>> for i in range(len(a)): b.append(tuple(a[i].values())) >>> b [('a', 'c', 'b'), ('e', 'd', 'f'), ('i', 'h', 'g')] >>> tuple(b) (('a', 'c', 'b'), ('e', 'd', 'f'), ('i', 'h', 'g')) >>> 我暂时还真想不到你这个list嵌套字典，又要全部转为tuple，却每步都要求不使用循环的处理方法。。。

[ucdosxp]

呵呵 谢谢了 因为zip可以实现两数组交叉混合，我想是否有函数可以实现分离

[ucdosxp]

那如果是这种该如何实现呢 a=[{"1":"a","2":["b","c"]},{"3":"d","4":["e","f"]},{"5":"g","6":["h","i"]}] 先需将a(字典型)转换成b(固定数组型) b=(("a","b","c"),("d","e","f"),("g","h","i"))

[panghuhu250]

引用 2 楼 ucdosxp 的回复:

呵呵 谢谢了 因为zip可以实现两数组交叉混合，我想是否有函数可以实现分离

还是zip。

In [146]: e = tuple(zip(*sorted(d.items()))[1] for d in a)

In [147]: e
Out[147]: (('a', 'b', 'c'), ('d', 'e', 'f'), ('g', 'h', 'i'))

In [148]: a
Out[148]: 
[{'1': 'a', '2': 'b', '3': 'c'},
 {'4': 'd', '5': 'e', '6': 'f'},
 {'7': 'g', '8': 'h', '9': 'i'}]