110,538
社区成员
发帖
与我相关
我的任务
分享http 发送指令
<html>
<body>
<!-- Send text to websocket -->
usrname:<input id="userName" type="textbox" value="lipeiji" style="background:yellow"/><br/>
message:<input id="userInput" type="textbox" value="test" style="background:Aqua"/><br/>
_notice:<input id="userNotice" type="textbox" value="lole" style="background:yellow"/><br/>
<button onclick="sendMessage('{act:LOGIN,usr:'+document.getElementById('userName').value+',msg:90283075428eb555f5d3959cddba3f85}')">登陆</button>
<button onclick="sendMessage('{act:ASK,usr:'+document.getElementById('userName').value+',msg:'+document.getElementById('userInput').value+'}')">请求</button>
<button onclick="sendMessage('{act:BROADCAST,usr:'+document.getElementById('userName').value+',msg:'+document.getElementById('userInput').value+'}')">广播</button>
<button onclick="sendMessage('{act:NOTICE,usr:'+document.getElementById('userNotice').value+',msg:'+document.getElementById('userInput').value+'}')">通知</button>
<!-- Results -->
<hr/>
输入：
<div id="inmessage"></div>
<hr/>
输出：
<div id="outmessage"></div>
<script>
function sendMessage(text) {
document.getElementById('inmessage').innerHTML = text;
ws.send(text);
}
function showMessage(text) {
document.getElementById('outmessage').innerHTML = text;
}
var ws = new WebSocket('ws://58.40.18.94:9200/do.wsk');
showMessage('Connecting...');
ws.onopen = function() { showMessage('Connected!'); };
ws.onclose = function() { showMessage('DisConnected!'); };
ws.onmessage = function(msg) { showMessage(msg.data); };
ws.onerror = function(msg) { showMessage(msg.data); };
</script>
</body>
</html>
这个是HTML的源码，可以直接运行点击登录返回！OK说明登录成功。 但是怎么该成WinFrom的。
链接地址：ws://58.40.18.94:9200/do.wsk
请求格式：{act:LOGIN,usr:'lipeiji',msg:"90283075428eb555f5d3959cddba3f85"}
响应：{"act":"LOGIN","usr":"lipeiji","msg":"!ok"}
msg为!ok表示成功，其他表示登陆失败。
求高手帮忙
...全文
请发表友善的回复…
发表回复
save4me 2014-06-26
- 打赏
- 举报
看一下我上面给你的两个链接，如果你用第二个开源项目的类的话，首页上面有个简单的使用示例。因为你发送和接收的是json，所以可以使用JsonWebSocket。下面的代码可以试一下，没有测试过，具体的可以下载源码看一下里面的示例。
using WebSocket4Net;
WebSocket websocket = new JsonWebSocket("ws://58.40.18.94:9200/do.wsk");
websocket.Opened += new EventHandler(websocket_Opened);
websocket.Closed += new EventHandler(websocket_Closed);
websocket.MessageReceived += new EventHandler<MessageReceivedEventArgs>(websocket_MessageReceived);
websocket.Error += new EventHandler<ErrorEventArgs>(websocket_Error);
websocket.Open();
private void websocket_Opened(object sender, EventArgs e)
{
showMessage("Connected!");
}
private void websocket_Closed(object sender, EventArgs e)
{
showMessage("DisConnected!");
}
private void websocket_MessageReceived(object sender, MessageReceivedEventArgs e)
{
showMessage(e.Message);
}
private void websocket_Error(object sender, ErrorEventArgs e)
{
showMessage(e.Message);
}
private void sendMessage(string text)
{
MessageBox.Show(text);
//websocket.Send(text, null);
websocket.Send("{act:LOGIN,usr:'lipeiji',msg:'90283075428eb555f5d3959cddba3f85'}", null);
}
private void showMessage(string text) {
MessageBox.Show(text);
}
baidu_16849617 2014-06-26
- 打赏
- 举报
我要把这个WebSocket编程的 改成WinFrom的。
baidu_16849617 2014-06-26
- 打赏
- 举报
#region httpwraper
public static ErrorType HttpRequest(out HttpResp resp)
{
resp = null;
string str = "{act:LOGIN,usr:'lipeiji',msg:"90283075428eb555f5d3959cddba3f85"}";
//log.Info(str);
byte[] data = Encoding.UTF8.GetBytes(str);
HttpWebRequest request = (HttpWebRequest)WebRequest.Create("http://ws://58.40.18.94:9200/do.wsk");
request.Timeout = 30000;
request.Credentials = CredentialCache.DefaultCredentials;
request.Proxy = GlobalProxySelection.GetEmptyWebProxy();
request.Method = "POST";
request.ContentLength = data.Length;
request.ContentType = "text/xml; charset=\"utf-8\"";
//ServicePointManager.Expect100Continue = false;
try
{
using (Stream streamBody = request.GetRequestStream())
{
streamBody.Write(data, 0, data.Length);
streamBody.Flush();
streamBody.Close();
}
HttpWebResponse response = (HttpWebResponse)request.GetResponse();
using (Stream dataStream = response.GetResponseStream())
{
if (dataStream == null)
{
return ErrorType.Failed;
}
TextReader reader = new StreamReader(dataStream, Encoding.UTF8);
string responseStr = reader.ReadToEnd();
HttpResp obj = XmlWrapper.Xml2Object(responseStr, typeof(HttpResp)) as HttpResp;
resp = obj;
if (obj == null)
{
log.ErrorFormat("UploadFailed, request = {0}, response = {1}", str, responseStr);
return ErrorType.Failed;
}
if (resp.st != "ok")
{
log.ErrorFormat("UploadFailed, request = {0}, response = {1}", str, responseStr);
return ErrorType.Failed;
}
TrySyncTime1(resp);
return ErrorType.Success;
}
}
catch (ThreadAbortException)
{
return ErrorType.Failed;
}
catch (ObjectDisposedException)
{
return ErrorType.Failed;
}
catch (SocketException ex)
{
return ErrorType.Failed;
}
catch (WebException ex)
{
request.Abort();
log.Debug(ex.Message);
//WebResponse wr = ex.Response;
//using (Stream stream = wr.GetResponseStream())
//{
// if (stream != null)
// {
// StreamReader streamReader = new StreamReader(stream, Encoding.Default);
// string strError = streamReader.ReadToEnd();
// streamReader.Close();
// }
//}
return ErrorType.NetworkError;
}
catch (Exception ex)
{
log.Error("错误:" + ex.ToString());
return ErrorType.Failed;
}
}
private static void TrySyncTime1(HttpResp resp)
{
try
{
if (resp == null || resp.Header == null)
{
return;
}
if (string.IsNullOrEmpty(resp.Header.time))
{
return;
}
DateTime serverTime = Convert.ToDateTime(resp.Header.time);
if (Math.Abs((serverTime - DateTime.Now).TotalSeconds) >= 180)
{
DateTimeHelper.LocalTime = serverTime;
}
}
catch (Exception)
{
}
}
#endregion
是这样的吧？ 但是一直报错说连接不是远程服务器。
save4me 2014-06-26
- 打赏
- 举报
HttpWebRequest是用来实现http协议的，你的是ws协议，比如http://ws://58.40.18.94:9200/do.wsk这个都根本不是合法的http地址，当然连接不上了。
walkeeper 2014-06-25
- 打赏
- 举报
用HttpWebRequest 朝这个地址发送请求
用HttpWebResponse获取响应的内容再解析JSON串来判断吧
save4me 2014-06-25
- 打赏
- 举报
使用WebSocket编程吧？可以参考一下:
.NET平台下websocket协议的实现！
或者开源项目
WebSocket4Net
wmg494005678 2014-06-24
- 打赏
- 举报
HttpWebRequest
