使用C语言实现bcd码转十六进制数。

Anastasia47 2014-07-10 08:30:06

BCD码（Binary-Coded Decimal）亦称二进码十进数或二-十进制代码。用4位二进制数来表示1位十进制数中的0-9这10个数码。例如：BCD码每四位表示一个十进制数。比如二进制数01111111，它对应的十进制数是127，1对应的BCD码（四位）为0001,2对应的BCD码为0010，7对应的BCD码为0111。合起来127对应的BCD码就是0001 0010 0111。
如何编程实现BCD码转十六进制数比如BCD码5（0101），怎么转成0x05？（使用C语言编程）。

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qq_39314918 2018-07-31

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uchar bcd_hex(uchar bcd) //bcdÂë×ª»»³É16½øÖÆÊý
{
uchar temp = bcd & 0x0f;
bcd = bcd >> 4;
bcd %= 0xf;

return bcd *10 + temp;
}

赵4老师 2014-07-11

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#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <locale.h>
int main() {
    int i,v;
    char bs[33];
    char b[33];
    char hs[9];
    char h[9];
    char s[4];
    char *e;

// 十进制整数转二进制串；
    i=1024;
    ltoa(i,b,2);
    sprintf(bs,"%032s",b);
    printf("i=%d,bs=%s\n",i,bs);
// 十进制整数转十六进制串；
    i=1024;
    ltoa(i,h,16);
    sprintf(hs,"%08s",h);
    printf("i=%d,hs=%s\n",i,hs);
// 十六进制字符串转成十进制数
    strcpy(hs,"00000400");
    sscanf(hs,"%x",&i);
    printf("hs=%s,i=%d\n",hs,i);
// 二进制字符串转化为十六进制字符串；
    strcpy(bs,"00000000000000000000010000000000");
    i=strtol(bs,&e,2);
    ltoa(i,h,16);
    sprintf(hs,"%08s",h);
    printf("bs=%s,hs=%s\n",bs,hs);
// 二进制字符串转化为十进制数；
    strcpy(bs,"00000000000000000000010000000000");
    i=strtol(bs,&e,2);
    printf("bs=%s,i=%d\n",bs,i);
// 十六进制字符串转成二进制串
    strcpy(hs,"00000400");
    sscanf(hs,"%x",&i);
    ltoa(i,b,2);
    sprintf(bs,"%032s",b);
    printf("hs=%s,bs=%s\n",hs,bs);
// ASC\GBK字符串转十六进制串
    strcpy(s,"a汉");
    i=0;
    while (1) {
        if (0==s[i]) break;
        sprintf(hs+i*2,"%02X",(unsigned char)s[i]);
        i++;
    }
    setlocale(LC_ALL,"chs");
    printf("s=%s,hs=%s\n",s,hs);
// 十六进制字符串转成汉字（GBK）及字符(ASC)
    strcpy(hs,"61BABA");
    i=0;
    while (1) {
        if (1!=sscanf(hs+i*2,"%2x",&v)) break;
        s[i]=(char)v;
        i++;
    }
    s[i]=0;
    printf("hs=%s,s=%s\n",hs,s);

    return 0;

}
//i=1024,bs=00000000000000000000010000000000
//i=1024,hs=00000400
//hs=00000400,i=1024
//bs=00000000000000000000010000000000,hs=00000400
//bs=00000000000000000000010000000000,i=1024
//hs=00000400,bs=00000000000000000000010000000000
//s=a汉,hs=61BABA
//hs=61BABA,s=a汉

赵4老师 2014-07-11

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仅供参考

#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
unsigned int iv,i;
unsigned char BCD[5];//定长10位BCD码
unsigned char sv[11];
void main() {
    iv=123456789;//最大10位无符号正整数
    //INT2BCD
    sprintf(sv,"%010u",iv);
    for (i=0;i<10;i+=2) {
        BCD[i/2]=(sv[i]<<4)|(sv[i+1]&0x0F);
    }
    printf("BCD=%02x%02x%02x%02x%02x\n",BCD[0],BCD[1],BCD[2],BCD[3],BCD[4]);
    //BCD2INT
    for (i=0;i<10;i+=2) {
        sv[i]='0'|(BCD[i/2]>>4);
        sv[i+1]='0'|(BCD[i/2]&0x0F);
    }
    sscanf(sv,"%010u",&iv);
    printf("iv=%010u\n",iv);
    getch();
}

zilaishuichina 2014-07-10

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	char *strBCD = "000100100111";
	int num = 0;
	for (int i = 4; i <= strlen(strBCD); i = i + 4)//长度不足4的部分将被舍去
	{
		num = num * 10 +
			(strBCD[i - 4] - '0') * 8 + 
			(strBCD[i - 3] - '0') * 4 + 
			(strBCD[i - 2] - '0') * 2 + 
			(strBCD[i - 1] - '0');
	}