go 的json解析问题

[Greg_han]

type Message struct {
Name string
Body string
Time int64
Parents *ParentS
}

type ParentS struct{
father string
mother string
}

pp := &ParentS{"Zhang","li"}


m := Message{"Alice", "Hello", 1294706395881547000,pp}

fmt.Println("father is",m.Parents.father)

x, err := json.Marshal(m)
if err != nil {
fmt.Printf("error is %v\n", err)
} else {
fmt.Printf("解析=%s",x)
}


///////////////////////////////输出怎样出现了 空{}？？？如下：
father is Zhang
解析={"Name":"Alice","Body":"Hello","Time":1294706395881547000,"Parents":{}}

[svenwang]

如果你要导出struct的成员，成员名的首字母要大写。 所以

type ParentS struct {
	father string
	mother string
}

要改成：

type ParentS struct {
	Father string
	Mother string
}

最终代码如下：

package main

import (
	"encoding/json"
	"fmt"
)

type Message struct {
	Name    string
	Body    string
	Time    int64
	Parents *ParentS
}

type ParentS struct {
	Father string
	Mother string
}

func main() {
	pp := &ParentS{"Zhang", "li"}
	m := Message{"Alice", "Hello", 1294706395881547000, pp}
	fmt.Println("father is", m.Parents.Father)
	x, err := json.Marshal(m)
	if err != nil {
		fmt.Printf("error is %v\n", err)
	} else {
		fmt.Printf("解析=%s", x)
	}
}

输出信息：

father is Zhang
解析={"Name":"Alice","Body":"Hello","Time":1294706395881547000,"Parents":{"Father":"Zhang","Mother":"li"}}