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分享到底要怎么才能在浏览器访问Servlet
用myEclipse创建了一个web项目名称叫做webDemo,然哦后在src中创建一个web包,然后就在里面直接创建一个Servlet,myEclipse就会自动帮我配置好web.xml,然后我就直接把生成的文件夹给复制到tomcat中的webapps中,但是无论如何都访问不了Servlet,到底是为什么!!!!!
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文哥xxx 2014-08-05
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是点击你的 项目 右键 啊
李狗剩 2014-08-04
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右键没有export啊
文哥xxx 2014-08-01
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项目右键export打成war包，放到tomcat的webapp目录下
S117 2014-08-01
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你要打成war包，放到tomcat的webapp目录下
tony4geek 2014-08-01
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把你的项目打成包，然后放tomact下
缘与我无缘 2014-08-01
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代码没有问题，运行结果
This is class web.First, using the GET method
检查下自己的运行环境
niuyongzljtoo 2014-08-01
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你没有发布成功，看看你MYECLIPSE对应的TOMCAT目录下SERVLET的CLASS文件是否生成了，在MYECLIPSE里面重新发布一下
李狗剩 2014-07-31
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上面那些不是代码?
李狗剩 2014-07-31
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我访问我这个工程的index.jsp就能成功,但是访问Servlet就是无论如何都是无法成功的
李狗剩 2014-07-31
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右键没有export war 这个选项
缘与我无缘 2014-07-31
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没有代码，无法查找原因
shixitong 2014-07-31
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把访问路径贴出来看看，是不是没加servlet
The_end90 2014-07-31
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Tomcat启动了吗？启动了以后浏览器输入-----localhost:8080/你的项目名/First
你的端口号是多少就把8080改成多少，如果你的 Web Context-root设置的是/，那就把上面的“你的项目名去掉”
姜小白- 2014-07-31
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工程 右键 export war 包 到 tomcat 的webapps 下面 ，tomcat 启动成功
http://localhost:8080/webDemo/servlet/First 红色部分根据实际情况更改
李狗剩 2014-07-31
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package web;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class First extends HttpServlet {
/**
* Constructor of the object.
*/
public First() {
super();
}
/**
* Destruction of the servlet. <br>
*/
public void destroy() {
super.destroy(); // Just puts "destroy" string in log
// Put your code here
}
/**
* The doGet method of the servlet. <br>
*
* This method is called when a form has its tag value method equals to get.
*
* @param request the request send by the client to the server
* @param response the response send by the server to the client
* @throws ServletException if an error occurred
* @throws IOException if an error occurred
*/
public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
response.setContentType("text/html");
PrintWriter out = response.getWriter();
out.println("<!DOCTYPE HTML PUBLIC \"-//W3C//DTD HTML 4.01 Transitional//EN\">");
out.println("<HTML>");
out.println(" <HEAD><TITLE>A Servlet</TITLE></HEAD>");
out.println(" <BODY>");
out.print(" This is ");
out.print(this.getClass());
out.println(", using the GET method");
out.println(" </BODY>");
out.println("</HTML>");
out.flush();
out.close();
}
/**
* The doPost method of the servlet. <br>
*
* This method is called when a form has its tag value method equals to post.
*
* @param request the request send by the client to the server
* @param response the response send by the server to the client
* @throws ServletException if an error occurred
* @throws IOException if an error occurred
*/
public void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
response.setContentType("text/html");
PrintWriter out = response.getWriter();
out.println("<!DOCTYPE HTML PUBLIC \"-//W3C//DTD HTML 4.01 Transitional//EN\">");
out.println("<HTML>");
out.println(" <HEAD><TITLE>A Servlet</TITLE></HEAD>");
out.println(" <BODY>");
out.print(" This is ");
out.print(this.getClass());
out.println(", using the POST method");
out.println(" </BODY>");
out.println("</HTML>");
out.flush();
out.close();
}
/**
* Initialization of the servlet. <br>
*
* @throws ServletException if an error occurs
*/
public void init() throws ServletException {
// Put your code here
}
}
李狗剩 2014-07-31
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<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.0"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
<servlet>
<servlet-name>First</servlet-name>
<servlet-class>web.First</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>First</servlet-name>
<url-pattern>/servlet/First</url-pattern>
</servlet-mapping>
</web-app>
