MultipartFile 如何释放正在打开的文件

2014-08-04 06:12:36 905 阅读 AI 写同款 · GEO 优化AI 选题数据监测一键分发 ›

MultipartFile读取本地文件、MultipartFile是否可以重复读取用MockMultipartFile即可，代码： public static void main(String[] args) throws Exception{ String fileName="in.txt"; String outFileName="out.txt"; try { File pdf = new File("d://"+fileName); MultipartFile multipartFile = new MockMultipar 阅读详情

/**

	 * 解压解析ZIP文件生成行程信息

	 * 

	 * @param file

	 * @throws IOException

	 * @throws IllegalStateException

	 */

	@Transactional

	@SuppressWarnings("rawtypes")

	public void doUploadVisitReportZip(MultipartFile file) throws IllegalStateException, IOException {

		FileOutputStream outStream = null;

		InputStream inputStream = null;

		try {

			// 创建新行程

			VisitReport visitReport = new VisitReport();



			// 上传的ZIP文件目录

			String zipCalculateRealPath = uploadFileService.zipCalculateRealPath() + File.separator;

			File saveFile = new File(zipCalculateRealPath + file.getOriginalFilename());

			// 保存ZIP文件到磁盘

			if (saveFile.exists()) {

				saveFile.delete();

			}

			if (!saveFile.exists()) {

				file.transferTo(saveFile);

			}

			// 读取ZIP文件

			ZipFile zipFile = new ZipFile(saveFile);

			// 遍历ZIP文件

			for (Enumeration entities = zipFile.getEntries(); entities.hasMoreElements();) {

				ZipEntry zipEntry = (ZipEntry) entities.nextElement();

				String unZipPath = ZipUtil.getUnZipPath(zipEntry.getName(), zipCalculateRealPath);

				File unZipFile = new File(unZipPath);

				ZipUtil.mkdirs(zipEntry, unZipFile);

				// 从ZIP条目获得输入流

				inputStream = zipFile.getInputStream(zipEntry);

				// 如果不是目录

				if (!zipEntry.isDirectory()) {

					outStream = new FileOutputStream(unZipFile);

					// 获得写入磁盘的输出流

					ZipUtil.write2Disk(outStream, inputStream);

				}

			}



			// 读取Excel生成行程Visit Report

			String excelFilePath = zipCalculateRealPath + uploadFileService.breakSuffix(file.getOriginalFilename())[0] + File.separator + "visit-info.xls";

			InputStream is = new FileInputStream(excelFilePath);

			// 读取excel属性赋值

			visitReport = readExcelContent(visitReport, is);



			dao.saveOrUpdate(visitReport);

		} catch (Exception e) {

			e.printStackTrace();

		} finally {

			try {

				if (outStream != null) {

					outStream.close();

				}

				if (inputStream != null) {

					inputStream.close();

				}

			} catch (IOException e) {

				e.printStackTrace();

			}

		}

如题，功能是上传一个zip到服务器，然后保存解压，解析里面的内容
File saveFile = new File(zipCalculateRealPath + file.getOriginalFilename());
// 保存ZIP文件到磁盘
if (saveFile.exists()) {
saveFile.delete();
}
if (!saveFile.exists()) {
file.transferTo(saveFile);
}
saveFile这个文件写入后，不能删除，导致上传重复名字的文件会有问题。
transferTo写入文件，如何释放，

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