strncpy复制字符串不能delete，strcpy却可以，为什么呢？

[IT保安]

构造函数

Bank::Bank(char * name,char * account,deposit amount)
{	
	int x = strlen(name);
	int y = strlen(account);
	Customer_Name = new char[x+1];
	Account = new char[y+1];
	strcpy(Customer_Name,name);
	strcpy(Account,account);
	//strncpy(Customer_Name,name,x);
	//strncpy(Account,account,y);
	//Customer_Name[x+1] = '\0';
	//Account[y+1] = '\0';
	Amount = amount;
}

析构函数

Bank::~Bank()
{
	delete [] Customer_Name;
	delete [] Account;
}

如题，我用strncpy复制字符串，编译通过，运行就错误了，后来忙半天试试改成了strcpy，就可以了！
这是为什么呢，不才的很，百度了一圈没看出个所以然！

另外问一个问题，在vc上面如果出错了，要进行调试，有哪本书是专门讲关于调试的知识呢，小弟自学者，很烦恼，只会F9，F5，每次看其他朋友的帖子，一堆的调试截图，看不明白啊，想学！

[帅得不敢出门]

//Customer_Name[x+1] = '\0'; //Account[y+1] = '\0'; 程序都越界了。出轨了。 夫妻生活能正常么

[IT保安]

如何理解越界了？我new的时候已经x+1 y+1了啊

[我看你有戏]

#include "iostream"
using namespace std;
void main()
{
	char *name="戏++学编程";
	char *account="www.vs2003.net";
	int x = strlen(name);
	int y = strlen(account);
	char* Customer_Name = new char[x+1];
	char* Account = new char[y+1];
	/*strcpy(Customer_Name,name);
	strcpy(Account,account);*/
	strncpy(Customer_Name,name,x);
	strncpy(Account,account,y);
	Customer_Name[x] = '\0';
	Account[y] = '\0';
	
	printf("%s:%s\n",Customer_Name,Account);

	system("pause");
}

离成功其实就是差那么一点，多加了个1 ，越界了

[hjl0508]

引用 3 楼 henry3695 的回复:

#include "iostream"
using namespace std;
void main()
{
	char *name="戏++学编程";
	char *account="www.vs2003.net";
	int x = strlen(name);
	int y = strlen(account);
	char* Customer_Name = new char[x+1];
	char* Account = new char[y+1];
	/*strcpy(Customer_Name,name);
	strcpy(Account,account);*/
	strncpy(Customer_Name,name,x);
	strncpy(Account,account,y);
	Customer_Name[x] = '\0';
	Account[y] = '\0';
	
	printf("%s:%s\n",Customer_Name,Account);

	system("pause");
}

离成功其实就是差那么一点，多加了个1 ，越界了

++ 楼主忽略了数组下标是从0开始的

Customer_Name[x+1] = '\0';

这个相当于赋值到x+2的位置了。。。

[阿麦]

构造和析构都没问题，应该是其他方面的。 对x+1，y+1我表示很认同。

[阿麦]

原来的（注释掉的）有问题， //strncpy(Customer_Name,name,x); //strncpy(Account,account,y); //Customer_Name[x+1] = '\0'; //Account[y+1] = '\0'; 应该是 //Customer_Name[x] = '\0'; //Account[y] = '\0';