为什么servlet获取不到$.ajax()传过来的数据

_阿坤 2014-08-27 01:04:09

//================JSP代码=================
sentData是测试发送的数据但是在servlet里接收不到，为什么？

<html>

  <head>

    

    <title>My JSP 'index.jsp' starting page</title>

    

  <script type="text/javascript">

	function _commit() {

		var sentData = {"name":"xxx","password":"我不好"};

		 $.ajax({

			 url:"${pageContext.request.contextPath}/ParseJsonServlet", //访问路径

             type:"POST",    //访问方式

             data:sentData, //传入服务端的数据

             dataType:"json",

             contentType:"application/json;charset=utf-8",

             success :function() {

            	$(document.forms[0]).remove();

 				$("#statuSpan").text("提交成功！");

             }

		 });

	}

  </script>

  <script type="text/javascript" src="js/jquery-1.5.1.js"></script></head>

  <body>

    <form action="" method="POST">

		<input type="text" name="name" value="Jack">

		<input type="text" name="description" value="My name is Jack">

		<input type="button" value="提交" onclick="_commit()">

	</form>

	<span id="statuSpan" ></span>

  </body>

</html>

//================Servlet代码=================



public class ParseJsonServlet extends HttpServlet {



    public void doGet(HttpServletRequest request, HttpServletResponse response)

	    throws ServletException, IOException {



    }



    public void doPost(HttpServletRequest request, HttpServletResponse response)

	    throws ServletException, IOException {

	request.setCharacterEncoding("UTF-8");

	System.out.println(request.getParameter("name"));

    }



}

...全文

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_阿坤 2014-08-27

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我找到两者解决方法第一种是将 $.ajax()里的 contentType:"application/json;charset=utf-8", 注释掉这样就可以通过


    request.setCharacterEncoding("UTF-8");
    System.out.println(request.getParameter("name"));

获取json参数值了第二种是将sentData加单引号改为var sentData =‘ {"name":"xxx","password":"我不好"}’; 这样可以通过


    	BufferedReader bufr = 
        	new BufferedReader(
        		new InputStreamReader(request.getInputStream(),"UTF-8"));
        StringBuilder sBuilder = new StringBuilder("");
        String temp = "";
        while((temp = bufr.readLine()) != null){
            sBuilder.append(temp);
        }
        bufr.close();
        String json = sBuilder.toString();
        System.out.println(json);

获取参数列表

斯洛文尼亚旅游 2014-08-27

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应该是乱码了。。好像java要调用2次encodeURIComponent来编码数据吧。。具体不懂java如何解码了

_阿坤 2014-08-27

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用以下代码可以获取，但中文显示不出来


    	BufferedReader bufr = 
        	new BufferedReader(
        		new InputStreamReader(request.getInputStream(),"UTF-8"));
        StringBuilder sBuilder = new StringBuilder("");
        String temp = "";
        while((temp = bufr.readLine()) != null){
            sBuilder.append(temp);
        }
        bufr.close();
        String json = sBuilder.toString();
        System.out.println(json);

输出结果为：name=xxx&description=%E6%88%91%E4%B8%8D%E5%A5%BD