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[seven002]

array ( 0 => array ( 'id' => '10', 'title' => 'a','type' => '1', 'bian'=>'1'),
1 => array ( 'id' => '10', 'title' => 'a','type' => '1', 'bian'=>2),
2 => array ( 'id' => '11', 'title' => 'b','type' => '2', 'bian'=>'1'),
3 => array ( 'id' => '11', 'title' => 'c','type' => '2', 'bian'=>'2'),
)
当type=1去除相同id重复并且key变成ID，当type=2时KEY变成id_bian的形式,最终转成以下数组
array ( 0 => array ( '10' => '', '11_1' => '','11_2' => ''),)
然后在与下面数组合并
array ( 0 => array ( '10' => '1','11_2' => '1'),
1 => array ( '10' => '1','11_2' => '1'),
2 => array ( '11_1' => '1','11_2' => '1'),
3 => array ( '10' => '2','11_2' => '1'),
)
最终得到
array ( 0 => array ( '10' => '1','11_1'=>'','11_2' => '1'),
1 => array ( '10' => '1', '11_1 => '', 11_2' => '1'),
2 => array ( '10' => '', '11_1' => '1', '11_2' => '1'),
3 => array ( '10' => '2', '11_1' => '', '11_2' => '1'),
)

[seven002]

引用 1 楼 xuzuning 的回复:

$a = array (
 0 => array ( 'id' => '10', 'title' => 'a','type' => '1', 'bian'=>'1'), 
 1 => array ( 'id' => '10', 'title' => 'a','type' => '1', 'bian'=>'2'), 
 2 => array ( 'id' => '11', 'title' => 'b','type' => '2', 'bian'=>'1'),
 3 => array ( 'id' => '11', 'title' => 'c','type' => '2', 'bian'=>'2'),  
);
$b = array (
 0 => array ( '10' => '1','11_2' => '1'), 
 1 => array ( '10' => '1','11_2' => '1'),
 2 => array ( '11_1' => '1','11_2' => '1'),
 3 => array ( '10' => '2','11_2' => '1'),  
);
$t = array();
foreach($a as $item) {
  if($item['type'] == '1') {
    $t[$item['id']] = '';
  }else $t[$item['id'].'_'.$item['bian']] = '';
}
$c = array();
foreach($b as $v) {
  $r = array();
  foreach($t as $k=>$n) $r[$k] = @$v[$k];
  $c[] = $r;
}
print_r($c);

Array
(
    [0] => Array
        (
            [10] => 1
            [11_1] => 
            [11_2] => 1
        )

    [1] => Array
        (
            [10] => 1
            [11_1] => 
            [11_2] => 1
        )

    [2] => Array
        (
            [10] => 
            [11_1] => 1
            [11_2] => 1
        )

    [3] => Array
        (
            [10] => 2
            [11_1] => 
            [11_2] => 1
        )

)

如果在$C里追加$t做为元素是不是要重新遍历？ 追加 array ( '10' => '', '11_1' => '','11_2' => '')做为$c的

[xuzuning]

不太明白你的意思

[seven002]

引用 3 楼 xuzuning 的回复:

不太明白你的意思

$a = array (
 0 => array ( 'id' => '10', 'title' => 'a','type' => '1', 'bian'=>'1'), 
 1 => array ( 'id' => '10', 'title' => 'a','type' => '1', 'bian'=>'2'), 
 2 => array ( 'id' => '11', 'title' => 'b','type' => '2', 'bian'=>'1'),
 3 => array ( 'id' => '11', 'title' => 'c','type' => '2', 'bian'=>'2'),  
);
$b = array (
 0 => array ( '10' => '1','11_2' => '1'), 
 1 => array ( '10' => '1','11_2' => '1'),
 2 => array ( '11_1' => '1','11_2' => '1'),
 3 => array ( '10' => '2','11_2' => '1'),  
);
$t = array();
foreach($a as $item) {
  if($item['type'] == '1') {
    $t[$item['id']] = '';
  }else $t[$item['id'].'_'.$item['bian']] = '';
}
$c = array();
foreach($b as $v) {
  $r = array();
  foreach($t as $k=>$n) $r[$k] = @$v[$k];
  $c[] = $r;
}
print_r($c);

就是数组a整里的结果插到$c中，是不是一定要把$c在遍历一次？

[xuzuning]

并没有遍历 $c 啊

[xuzuning]

$a = array (
 0 => array ( 'id' => '10', 'title' => 'a','type' => '1', 'bian'=>'1'), 
 1 => array ( 'id' => '10', 'title' => 'a','type' => '1', 'bian'=>'2'), 
 2 => array ( 'id' => '11', 'title' => 'b','type' => '2', 'bian'=>'1'),
 3 => array ( 'id' => '11', 'title' => 'c','type' => '2', 'bian'=>'2'),  
);
$b = array (
 0 => array ( '10' => '1','11_2' => '1'), 
 1 => array ( '10' => '1','11_2' => '1'),
 2 => array ( '11_1' => '1','11_2' => '1'),
 3 => array ( '10' => '2','11_2' => '1'),  
);
$t = array();
foreach($a as $item) {
  if($item['type'] == '1') {
    $t[$item['id']] = '';
  }else $t[$item['id'].'_'.$item['bian']] = '';
}
$c = array();
foreach($b as $v) {
  $r = array();
  foreach($t as $k=>$n) $r[$k] = @$v[$k];
  $c[] = $r;
}
print_r($c);

Array
(
    [0] => Array
        (
            [10] => 1
            [11_1] => 
            [11_2] => 1
        )

    [1] => Array
        (
            [10] => 1
            [11_1] => 
            [11_2] => 1
        )

    [2] => Array
        (
            [10] => 
            [11_1] => 1
            [11_2] => 1
        )

    [3] => Array
        (
            [10] => 2
            [11_1] => 
            [11_2] => 1
        )

)

[seven002]

引用 7 楼 xuzuning 的回复:

怎么插？插在哪个部位？ $c 的每个成员都含有 $t 的键

Array ( 0=> array ( '10' => '', '11_1' => '','11_2' => '')//就插在这里 [0] => Array ( [10] => 1 [11_1] => [11_2] => 1 ) [1] => Array ( [10] => 1 [11_1] => [11_2] => 1 ) [2] => Array ( [10] => [11_1] => 1 [11_2] => 1 ) [3] => Array ( [10] => 2 [11_1] => [11_2] => 1 ) )

[xuzuning]

如果你一开始就打算放进去，那么 $c = array(); 改为 $c = array($t);

[seven002]

引用 5 楼 xuzuning 的回复:

并没有遍历 $c 啊

这么说吧。现在$t是整理$a得到的数组，$c是合并$t和$b。我想在$c里在插入$t。版主应该怎么改？

[xuzuning]

怎么插？插在哪个部位？ $c 的每个成员都含有 $t 的键