VS2013写的一个简单计算器编译不了

[cc187299067]

#include<stdio.h>
int main(void) //*计算器
{
double shuzi = 0.0;
double shuzi1 = 0.0;
char fuhao = 0;

printf("请输入一个计算：");
scanf_s("%lf %c %lf", &shuzi, &fuhao, &shuzi1);


switch (fuhao)
{
case '+':
printf("=%lf\n", shuzi + shuzi1);
break;
case '-':
printf("=%lf\n", shuzi - shuzi1);
break;
case '*':
printf("=%lf\n", shuzi * shuzi1);
break;
case '/':
if (shuzi1 == 0)
printf("输入错误");
else
printf("=%lf", shuzi / shuzi1);
break;
case '%':
if (shuzi1 == 0)
printf("输入错误");
else
printf("=%lf", (long)shuzi % (long)shuzi1);
break;
default:
printf("\n\n输入错误\n\n");
}
return 0;
｝


求大神帮忙看看

[cdsnfresh]

估计死在scanf_s（）上了，http://msdn.microsoft.com/zh-cn/library/w40768et%28VS.80%29.aspx，http://baike.baidu.com/view/3529726.htm?fr=aladdin，不是windows不能测试scanf_s（）

[YinQingwei1986]

改为scanf_s("%lf %c %lf", &shuzi, &fuhao,1, &shuzi1); 即在第二个参数后加一个参数1 或把scanf_s改为scanf 原因：scanf_f在输入字符或者字符串时会有边界检查，需要输入最多输入多少个字符的个数的参数

[xiaohuh421]

result = scanf_s( "%d %f %c %C %s %S", &i, &fp, &c, 1, &wc, 1, s, 80, ws, 80 ); 注意跟上每个数据的大小.