关于android的listView排序问题...

WellerV 2014-09-23 09:21:27

写一个播放器，显示播放列表按照首字母排序，字母排在汉字前面。
ListView的适配器里面有这样一个方法，所以自己构造了一个类SongComparator继承自Comparator

		mSortAdapter.sort(new SongComparator());

package com.huwei.sweetmusicplayer.comparator;



import java.util.Comparator;



import com.huwei.sweetmusicplayer.models.Song;

import com.huwei.sweetmusicplayer.util.CharacterParser;



 

public class SongComparator implements Comparator<Song> {



	@Override

	public int compare(Song song1, Song song2) {

		// TODO Auto-generated method stub

		// boolean isLetter1;

		// boolean isLetter2;

		// 得到歌曲名



		String title1 ;

		String title2 ;

		int isLetter1_m ;

		int isLetter2_m ;

		boolean isLetter1 ;

		boolean isLetter2 ;



	 

			title1 = song1.getName();

			title2 = song2.getName();



			if (title1.equals("啊啊啊啊") || title2.equals("啊啊啊啊")) {

				System.out.println();   //断点位置

			}



			isLetter1_m = CharacterParser.firstIsLetter(title1);

			isLetter2_m = CharacterParser.firstIsLetter(title2);



			isLetter1 = (isLetter1_m == 0) ? false:true;

			isLetter2 = (isLetter2_m == 0) ? false:true;

 



	 



		// if(isLetter1_m!=0){

		// isLetter1=true;

		// }else {

		// isLetter1=false;

		// }

		//

		// if(isLetter2_m!=0){

		// isLetter2=true;

		// }else {

		// isLetter2=false;

		// }



		// isLetter1=true;

		// isLetter2=false;

		if (isLetter1 && isLetter2) {

			// 第一个是小写，第二个是大写

			if (isLetter1_m < isLetter2_m) {

				return -1;

			}// 第一个是大写，第一个是小写

			else if (isLetter1_m > isLetter2_m) {

				return 1;

			}// 大小写情况相同

			else {

				return CharacterParser.getFirstLetter(title1).charAt(0)

						- CharacterParser.getFirstLetter(title2).charAt(0);

			}

		} else if (isLetter1) {

			return -1;

		} else if (isLetter2) {

			return 1;

		} else {

			return CharacterParser.getFirstLetter(title1).charAt(0)

					- CharacterParser.getFirstLetter(title2).charAt(0);

		}

	}



}

现在的问题是调试时发现在判断else if (isLetter1)时，不进入下一个判断else if (isLetter2)，而直接跳到了最后一个else，有时看到isLetter1，isLetter2时空的，有时不是的。我把断点设置在System.out.println();为了保证有一个是汉字。

如果有需要我可以把整个工程发上来。

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WellerV 2014-10-06

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引用 21 楼 svenwang 的回复:

我试过了。这其实是个假象，调试器似乎总是跳到会最后一个return语句，但其实这里并没有执行最后一个return，实际执行的还是if (isLetter1)这个分支，最后返回的结果是-1。如果你把if (isLetter1)分支语句多写几句再调试一下就看得更清楚了：
else if (isLetter1) {
	int result = 1; // 这里下调试断点
	result *= -1;
	return result;
} else if (isLetter2) {
为什么会这么奇怪呢，我猜测是因为函数编译出来其实只有一个return，并把最后一个return作为真正执行return的语句，所以无论如何都会跳到最后一个return，但函数计算结果是正确的。

我再看看啊.....你说的好像有点道理

WellerV 2014-10-04

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引用 17 楼 svenwang 的回复:

[quote=引用 16 楼 huweigoodboy 的回复:] [quote=引用 14 楼 svenwang 的回复:] [quote=引用 13 楼 huweigoodboy 的回复:] [quote=引用 12 楼 windsunmoon 的回复:] 这种效果，我实现的有自定义控件，见博客
http://blog.csdn.net/windsunmoon/article/details/39163023
里面很详细

我的compareTo()比你这个复杂点，我想实现字母排在汉字前面，小写字母排在大小字母前面，所以有了上图中的代码。但是比较的时候，有个if就是不进去。[/quote] 那是因为你的代码逻辑有问题。[/quote] 是有问题才发上来嘛！ if(true)进不去是不是太诡异了？难道compareTo会涉及到多线程？调试发现只是在mainThread里面调用的。[/quote] 你可以把完整的代码发上来看看。现在没有Song的代码，也不知道你传递给compare的两个对象的值是什么，所以没有办法做进一步的分析。[/quote] 代码在18，19楼，如果觉得还是看不清，我就把代码弄个链接吧。

WellerV 2014-10-04

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提取首字母，还有判断第一个字母是否是英文的工具类

package com.huwei.sweetmusicplayer.util;

import java.io.UnsupportedEncodingException;
 
/*
 * java汉字转拼音*/
public class CharacterParser {
	//private static LinkedHashMap<String, Integer> spellMap;;
	private static int[] pyvalue = new int[] {-20319, -20317, -20304, -20295, -20292, -20283, -20265, -20257, -20242, -20230, -20051, -20036, -20032,  
        -20026, -20002, -19990, -19986, -19982, -19976, -19805, -19784, -19775, -19774, -19763, -19756, -19751, -19746, -19741, -19739, -19728,  
        -19725, -19715, -19540, -19531, -19525, -19515, -19500, -19484, -19479, -19467, -19289, -19288, -19281, -19275, -19270, -19263, -19261,  
        -19249, -19243, -19242, -19238, -19235, -19227, -19224, -19218, -19212, -19038, -19023, -19018, -19006, -19003, -18996, -18977, -18961,  
        -18952, -18783, -18774, -18773, -18763, -18756, -18741, -18735, -18731, -18722, -18710, -18697, -18696, -18526, -18518, -18501, -18490,  
        -18478, -18463, -18448, -18447, -18446, -18239, -18237, -18231, -18220, -18211, -18201, -18184, -18183, -18181, -18012, -17997, -17988,  
        -17970, -17964, -17961, -17950, -17947, -17931, -17928, -17922, -17759, -17752, -17733, -17730, -17721, -17703, -17701, -17697, -17692,  
        -17683, -17676, -17496, -17487, -17482, -17468, -17454, -17433, -17427, -17417, -17202, -17185, -16983, -16970, -16942, -16915, -16733,  
        -16708, -16706, -16689, -16664, -16657, -16647, -16474, -16470, -16465, -16459, -16452, -16448, -16433, -16429, -16427, -16423, -16419,  
        -16412, -16407, -16403, -16401, -16393, -16220, -16216, -16212, -16205, -16202, -16187, -16180, -16171, -16169, -16158, -16155, -15959,  
        -15958, -15944, -15933, -15920, -15915, -15903, -15889, -15878, -15707, -15701, -15681, -15667, -15661, -15659, -15652, -15640, -15631,  
        -15625, -15454, -15448, -15436, -15435, -15419, -15416, -15408, -15394, -15385, -15377, -15375, -15369, -15363, -15362, -15183, -15180,  
        -15165, -15158, -15153, -15150, -15149, -15144, -15143, -15141, -15140, -15139, -15128, -15121, -15119, -15117, -15110, -15109, -14941,  
        -14937, -14933, -14930, -14929, -14928, -14926, -14922, -14921, -14914, -14908, -14902, -14894, -14889, -14882, -14873, -14871, -14857,  
        -14678, -14674, -14670, -14668, -14663, -14654, -14645, -14630, -14594, -14429, -14407, -14399, -14384, -14379, -14368, -14355, -14353,  
        -14345, -14170, -14159, -14151, -14149, -14145, -14140, -14137, -14135, -14125, -14123, -14122, -14112, -14109, -14099, -14097, -14094,  
        -14092, -14090, -14087, -14083, -13917, -13914, -13910, -13907, -13906, -13905, -13896, -13894, -13878, -13870, -13859, -13847, -13831,  
        -13658, -13611, -13601, -13406, -13404, -13400, -13398, -13395, -13391, -13387, -13383, -13367, -13359, -13356, -13343, -13340, -13329,  
        -13326, -13318, -13147, -13138, -13120, -13107, -13096, -13095, -13091, -13076, -13068, -13063, -13060, -12888, -12875, -12871, -12860,  
        -12858, -12852, -12849, -12838, -12831, -12829, -12812, -12802, -12607, -12597, -12594, -12585, -12556, -12359, -12346, -12320, -12300,  
        -12120, -12099, -12089, -12074, -12067, -12058, -12039, -11867, -11861, -11847, -11831, -11798, -11781, -11604, -11589, -11536, -11358,  
        -11340, -11339, -11324, -11303, -11097, -11077, -11067, -11055, -11052, -11045, -11041, -11038, -11024, -11020, -11019, -11018, -11014,  
        -10838, -10832, -10815, -10800, -10790, -10780, -10764, -10587, -10544, -10533, -10519, -10331, -10329, -10328, -10322, -10315, -10309,  
        -10307, -10296, -10281, -10274, -10270, -10262, -10260, -10256, -10254};  
public static String[] pystr = new String[] {"a", "ai", "an", "ang", "ao", "ba", "bai", "ban", "bang", "bao", "bei", "ben", "beng", "bi", "bian",  
        "biao", "bie", "bin", "bing", "bo", "bu", "ca", "cai", "can", "cang", "cao", "ce", "ceng", "cha", "chai", "chan", "chang", "chao", "che",  
        "chen", "cheng", "chi", "chong", "chou", "chu", "chuai", "chuan", "chuang", "chui", "chun", "chuo", "ci", "cong", "cou", "cu", "cuan",  
        "cui", "cun", "cuo", "da", "dai", "dan", "dang", "dao", "de", "deng", "di", "dian", "diao", "die", "ding", "diu", "dong", "dou", "du",  
        "duan", "dui", "dun", "duo", "e", "en", "er", "fa", "fan", "fang", "fei", "fen", "feng", "fo", "fou", "fu", "ga", "gai", "gan", "gang",  
        "gao", "ge", "gei", "gen", "geng", "gong", "gou", "gu", "gua", "guai", "guan", "guang", "gui", "gun", "guo", "ha", "hai", "han", "hang",  
        "hao", "he", "hei", "hen", "heng", "hong", "hou", "hu", "hua", "huai", "huan", "huang", "hui", "hun", "huo", "ji", "jia", "jian",  
        "jiang", "jiao", "jie", "jin", "jing", "jiong", "jiu", "ju", "juan", "jue", "jun", "ka", "kai", "kan", "kang", "kao", "ke", "ken",  
        "keng", "kong", "kou", "ku", "kua", "kuai", "kuan", "kuang", "kui", "kun", "kuo", "la", "lai", "lan", "lang", "lao", "le", "lei", "leng",  
        "li", "lia", "lian", "liang", "liao", "lie", "lin", "ling", "liu", "long", "lou", "lu", "lv", "luan", "lue", "lun", "luo", "ma", "mai",  
        "man", "mang", "mao", "me", "mei", "men", "meng", "mi", "mian", "miao", "mie", "min", "ming", "miu", "mo", "mou", "mu", "na", "nai",  
        "nan", "nang", "nao", "ne", "nei", "nen", "neng", "ni", "nian", "niang", "niao", "nie", "nin", "ning", "niu", "nong", "nu", "nv", "nuan",  
        "nue", "nuo", "o", "ou", "pa", "pai", "pan", "pang", "pao", "pei", "pen", "peng", "pi", "pian", "piao", "pie", "pin", "ping", "po", "pu",  
        "qi", "qia", "qian", "qiang", "qiao", "qie", "qin", "qing", "qiong", "qiu", "qu", "quan", "que", "qun", "ran", "rang", "rao", "re",  
        "ren", "reng", "ri", "rong", "rou", "ru", "ruan", "rui", "run", "ruo", "sa", "sai", "san", "sang", "sao", "se", "sen", "seng", "sha",  
        "shai", "shan", "shang", "shao", "she", "shen", "sheng", "shi", "shou", "shu", "shua", "shuai", "shuan", "shuang", "shui", "shun",  
        "shuo", "si", "song", "sou", "su", "suan", "sui", "sun", "suo", "ta", "tai", "tan", "tang", "tao", "te", "teng", "ti", "tian", "tiao",  
        "tie", "ting", "tong", "tou", "tu", "tuan", "tui", "tun", "tuo", "wa", "wai", "wan", "wang", "wei", "wen", "weng", "wo", "wu", "xi",  
        "xia", "xian", "xiang", "xiao", "xie", "xin", "xing", "xiong", "xiu", "xu", "xuan", "xue", "xun", "ya", "yan", "yang", "yao", "ye", "yi",  
        "yin", "ying", "yo", "yong", "you", "yu", "yuan", "yue", "yun", "za", "zai", "zan", "zang", "zao", "ze", "zei", "zen", "zeng", "zha",  
        "zhai", "zhan", "zhang", "zhao", "zhe", "zhen", "zheng", "zhi", "zhong", "zhou", "zhu", "zhua", "zhuai", "zhuan", "zhuang", "zhui",  
        "zhun", "zhuo", "zi", "zong", "zou", "zu", "zuan", "zui", "zun", "zuo"};  
	
	
	private static CharacterParser instance;
	
 
	
	private StringBuilder resource;
	//单例模式
	public CharacterParser getInstance(){
		if(instance==null) {
			instance=new CharacterParser();
 
		}
			return instance;
	}
	
	public StringBuilder getResource() {
		return resource;
	}


	public void setResource(StringBuilder resource) {
		this.resource = resource;
	}

 
	
	//单个汉字转成ansi
	public static int getChsAscii(String chs){
		int asc=0;
		
		try {
			byte[] bytes=chs.getBytes("gb2312");
			
			if(bytes==null||bytes.length==0){
				throw new RuntimeException("illegal resource string");
			}
			
			if(bytes.length==1){	//英文字符
				asc=bytes[0];
			}
			
			if(bytes.length==2){	//中文字符
				int highByte=256+bytes[0];
				int lowByte=256+bytes[1];
				
				asc=(256*highByte+lowByte)-256*256;	
			}
		} catch (UnsupportedEncodingException e) {
			// TODO Auto-generated catch block
			e.printStackTrace();
		}
		
		return asc;
	}
 
	
	//首字符是否是字母
	//大写return 1 小写return -1 非retrun 0
	public static int firstIsLetter(String name){
		int asc=getChsAscii(name.substring(0,1));
		if( asc>='A'&&asc<='Z'){//单字符
			return 1;
		}else if(asc>='a'&&asc<='z'){
			return -1;
		}else{
			return 0;
		}
		 
	}
	
	//提取首字母，大小写均可
	public static String getSpellByAscii(int asc){
		String res=null;
		if(asc>0&&asc<160){//单字符
			res=String.valueOf((char)asc);
		}
		else if (asc< -20319 || asc > -10247) { //未知字符
	           return null;
	    }  
	  
 
		else {
			for(int i=pyvalue.length-1;i>=0;i--){
				if(asc>=pyvalue[i]){
					res=pystr[i];
					break;
				}
			}
		}
		
		//提取首字母
		res=res.substring(0,1);
		
 
 
	    return res;
	}
	//获取首字母的大写字母
	public static String getFirstUpperLetter(String cn){
		return getFirstLetter(cn).toUpperCase();
	}
	
	
	//获取首字母
	public static String getFirstLetter(String cn){
		return getSpellByAscii(getChsAscii(cn.substring(0, 1)));
	}
	
	//获取全拼
	public static String getFullSpell(String cn){
		String resString=null;
		for(int i=0;i<cn.length();i++){
			String string=cn.substring(i, i+1);
			resString+=getSpellByAscii(getChsAscii(string));
		}
		return resString;
	}

}

然后就调用了ListView排序的方法。现在的问题就是英文排不到中文前面去，调试发现有个if进不去。

WellerV 2014-10-04

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Comparator

package com.huwei.sweetmusicplayer.comparator;

import java.util.Comparator;

import com.huwei.sweetmusicplayer.models.Song;
import com.huwei.sweetmusicplayer.util.CharacterParser;

 
public class SongComparator implements Comparator<Song> {

	@Override
	public int compare(Song song1, Song song2) {
		// TODO Auto-generated method stub
		// boolean isLetter1;
		// boolean isLetter2;
		// 得到歌曲名

		String title1 ;
		String title2 ;
		int isLetter1_m ;
		int isLetter2_m ;
		boolean isLetter1 ;
		boolean isLetter2 ;

	 
			title1 = song1.getTitle();
			title2 = song2.getTitle();

			if (title1.equals("bg_reloj") || title2.equals("bg_reloj")) {
				System.out.println();
			}

			isLetter1_m = CharacterParser.firstIsLetter(title1);
			isLetter2_m = CharacterParser.firstIsLetter(title2);

//			isLetter1 = (isLetter1_m == 0) ? false:true;
//			isLetter2 = (isLetter2_m == 0) ? false:true;
 

	 

		 if(isLetter1_m!=0){
		 isLetter1=true;
		 }else {
		 isLetter1=false;
		 }
		
		 if(isLetter2_m!=0){
		 isLetter2=true;
		 }else {
		 isLetter2=false;
		 }

		// isLetter1=true;
		// isLetter2=false;
		if (isLetter1 && isLetter2) {
			// 第一个是小写，第二个是大写
			if (isLetter1_m < isLetter2_m) {
				return -1;
			}// 第一个是大写，第一个是小写
			else if (isLetter1_m > isLetter2_m) {
				return 1;
			}// 大小写情况相同
			else {
				return CharacterParser.getFirstLetter(title1).charAt(0)
						- CharacterParser.getFirstLetter(title2).charAt(0);
			}
		} else if (isLetter1) {
			return -1;
		} else if (isLetter2) {
			return 1;
		} else {
			return CharacterParser.getFirstLetter(title1).charAt(0)
					- CharacterParser.getFirstLetter(title2).charAt(0);
		}
	}

}

Song.java

package com.huwei.sweetmusicplayer.models;

import java.io.Serializable;

import com.huwei.sweetmusicplayer.util.CharacterParser;
import com.huwei.sweetmusicplayer.util.TimeUtil;

public class Song implements Serializable{
	private String title;	//歌曲名
	private int duration;	//时长
	private String artist;		//艺术家
	private int id;	//id
	private String display_name;
	private String data;
	private String date_added;
	
	private String path;
	private String sortLetters;	    //检索的首字母
 

	public int getId() {
		return id;
	}

	public void setId(int id) {
		this.id = id;
	}

	public String getDisplay_name() {
		return display_name;
	}

	public void setDisplay_name(String display_name) {
		this.display_name = display_name;
	}

	public String getData() {
		return data;
	}

	public void setData(String data) {
		this.data = data;
	}


	public String getDate_added() {
		return date_added;
	}

	public void setDate_added(String date_added) {
		this.date_added = date_added;
	}

	public Song(){
		
	}
	
	public Song(String title){
		super();
		this.title=title;
		
		if(title.equals("安居客")) 
			{
			System.out.println();
			}
		
		String firstLetter=CharacterParser.getFirstLetter(title);
		//正则匹配 ,匹配大小写字母
		if(firstLetter.matches("^[a-zA-Z]$")){
			this.sortLetters=firstLetter.toUpperCase();
		}else{
			this.sortLetters="#";
		}
	}
	
	public Song(String title, String sortLetters) {
		super();
		this.title = title;
		this.sortLetters = sortLetters;
	}


 
	public String getTitle() {
		return title;
	}

	public void setTitle(String title) {
		this.title = title;
	}

	public String getSortLetters() {
		return CharacterParser.getFirstUpperLetter(title);
	}
	public void setSortLetters(String sortLetters) {
		this.sortLetters = sortLetters;
	}

 

	public String getDurationTime(){
		return TimeUtil.toTime(duration);
	}

	public int getDuration() {
		return duration;
	}

	public void setDuration(int duration) {
		this.duration = duration;
	}

	public String getArtist() {
		return artist;
	}

	public void setArtist(String artist) {
		this.artist = artist;
	}

	public String getPath() {
		return path;
	}

	public void setPath(String path) {
		this.path = path;
	}
	
}

svenwang 2014-10-04

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我试过了。这其实是个假象，调试器似乎总是跳到会最后一个return语句，但其实这里并没有执行最后一个return，实际执行的还是if (isLetter1)这个分支，最后返回的结果是-1。如果你把if (isLetter1)分支语句多写几句再调试一下就看得更清楚了：


else if (isLetter1) {
	int result = 1; // 这里下调试断点
	result *= -1;
	return result;
} else if (isLetter2) {

为什么会这么奇怪呢，我猜测是因为函数编译出来其实只有一个return，并把最后一个return作为真正执行return的语句，所以无论如何都会跳到最后一个return，但函数计算结果是正确的。

svenwang 2014-10-03

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引用 16 楼 huweigoodboy 的回复:

[quote=引用 14 楼 svenwang 的回复:] [quote=引用 13 楼 huweigoodboy 的回复:] [quote=引用 12 楼 windsunmoon 的回复:] 这种效果，我实现的有自定义控件，见博客
http://blog.csdn.net/windsunmoon/article/details/39163023
里面很详细

WellerV 2014-10-03

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引用 14 楼 svenwang 的回复:

[quote=引用 13 楼 huweigoodboy 的回复:] [quote=引用 12 楼 windsunmoon 的回复:] 这种效果，我实现的有自定义控件，见博客
http://blog.csdn.net/windsunmoon/article/details/39163023
里面很详细

哈哈gogo 2014-10-02

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顶你一个好哪

svenwang 2014-10-01

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引用 13 楼 huweigoodboy 的回复:

[quote=引用 12 楼 windsunmoon 的回复:] 这种效果，我实现的有自定义控件，见博客
http://blog.csdn.net/windsunmoon/article/details/39163023
里面很详细

我的compareTo()比你这个复杂点，我想实现字母排在汉字前面，小写字母排在大小字母前面，所以有了上图中的代码。但是比较的时候，有个if就是不进去。[/quote] 那是因为你的代码逻辑有问题。

WellerV 2014-10-01

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引用 12 楼 windsunmoon 的回复:

这种效果，我实现的有自定义控件，见博客
http://blog.csdn.net/windsunmoon/article/details/39163023
里面很详细

我的compareTo()比你这个复杂点，我想实现字母排在汉字前面，小写字母排在大小字母前面，所以有了上图中的代码。但是比较的时候，有个if就是不进去。

windsunmoon 2014-09-30

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这种效果，我实现的有自定义控件，见博客

http://blog.csdn.net/windsunmoon/article/details/39163023

里面很详细

WellerV 2014-09-30

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引用 10 楼 HonestHuang430 的回复:

if(false) 怎么可能进去啊

是if(true）啊，isLetter1=true,所以if(isLetter1)应该进去啊。

WellerV 2014-09-29

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引用 7 楼 rover11 的回复:

怎么感觉像多线程干扰了? 打印个Thread id 看看?

不行啊，compare方法都是在main线程里面。

黄诚实_ 2014-09-29

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if(false) 怎么可能进去啊

WellerV 2014-09-25

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引用 7 楼 rover11 的回复:

怎么感觉像多线程干扰了? 打印个Thread id 看看?

我试试吧

WellerV 2014-09-24

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引用 4 楼 lionfresh 的回复:

觉得是调试器出问题了，重新一下开发环境。

在别人的编译器环境里调试也是这样的，要不我把代码给你，你试试。但是第一次进入Comparator时，四个判断都会运行，而第二次进入，就不会走四个判断，直接跳到最后一个。

WellerV 2014-09-24

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引用 3 楼 YKDSea 的回复:

“isLetter1，isLetter2时空的”这是什么意思？没有值？如果是的话，我觉得你要先检查这个，在前面吧isLetter1,isLetter2打印出来看下

我直接进入调试的，没表达清楚，就是isLetter1=false isLetter2=true时，不进行第三个if判断，然后直接跳到最后一个return了。

lionfresh 2014-09-24

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觉得是调试器出问题了，重新一下开发环境。

sky-Z 2014-09-24

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“isLetter1，isLetter2时空的”这是什么意思？没有值？如果是的话，我觉得你要先检查这个，在前面吧isLetter1,isLetter2打印出来看下

rover11 2014-09-24

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怎么感觉像多线程干扰了? 打印个Thread id 看看?

原项目实现了ListView的拖动排序功能. 在此基础上添加了 1.单选/多选功能. 其实这些功能都比较零散,只是那些天碰巧把这些功能都在这个项目里做了实现. 可以适当选择使用. ###问题### 滑动删除,对手势的识别不太理想.我将这些值都调到尽可能小,只是实现区分的作用.可能根据项目情况,再进行调节.

看效果直接去bin文件夹将MainActivity.apk文件安装到模拟器即可查看效果。

Android实现ListView的A-Z字母排序和过滤搜索功能,完整源码，小伙伴需要的来CSDN下载吧！项目详情http://blog.csdn.net/xiaanming/article/details/12684155

Android ListView的字母索引排序和搜索，http://blog.csdn.net/yalinfendou博客中有详细介绍……

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