用java打印出数组中不同的元素,比如int[] a=new[]{2,4,5,6,3}和int[] b=new[]{1,4,8,6,9}哪位大侠能帮我!急!

[baidu_21279683]

用java打印出数组中不同的元素,比如int[] a=new[]{2,4,5,6,3}和int[] b=new[]{1,4,8,6,9}
/*
结果输出1, 8, 9

**/

[Sauron1]

public class Test{
	public static void main(String[] args) {
		int numA[] = {2,4,5,6,3};
		int numB[] = {1,4,8,6,9};
		LinkedList<Integer> difNumList = new LinkedList<Integer>();
		
		getDifNum(numA,numB,difNumList);
		print(difNumList);
	}
	public static void getDifNum(int numA[],int numB[],LinkedList<Integer> difNumList)
	{
		boolean same = false;
		for(int i = 0; i < numA.length; ++i)
		{
			for(int j = 0; j < numB.length; ++j)
				if(numA[i] == numB[j])
				{
					same = true;
					break;
				}
			if(same != true)
				difNumList.add(numA[i]);
			same = false;
		}
	}
	public static void print(LinkedList<Integer> difNumList)
	{
		for(int i = 0; i < difNumList.size(); ++i)
			System.out.print(difNumList.get(i) + " ");
	}
}

[scott_129]

楼上的这种方式可以， 不过感觉应该在效率上还可以优化。

[xiaolong806124]

public static void main(String[] args) {
		int numA[] = { 2, 4, 5, 6, 3 };
		int numB[] = { 1, 4, 8, 6, 9, 2 };
		for (int i : numB) {
			boolean flag = false;
			for (int j : numA) {
				if (j == i) {
					flag = true;
					break;
				}
			}
			if(!flag)System.out.print(i+ "   ");
		}
	}

[GeekStuff]

public static void getDifNum(int numA[],int numB[])
    {
         Set<Integer> set = new HashSet<Integer>(Arrays.asList(numA));
         for(int i : numB) {
            if(!set.contains(i)) {
                   System.out.print(i+ "   ");
             }
          }
    }