未找到持久化单元错误?
Mr_Y_ 2014-10-15 12:35:00
persistence.xml
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.1"
xmlns="http://xmlns.jcp.org/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/persistence
http://xmlns.jcp.org/xml/ns/persistence/persistence_2_1.xsd">
<persistence-unit name="jpaUnit" transaction-type="RESOURCE_LOCAL">
<provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
<class>com.c4c.entity.User</class>
<properties>
<property name="javax.persistence.jdbc.driver"
value="com.mysql.jdbc.Driver"/>
<property name="javax.persistence.jdbc.url"
value="jdbc:mysql://localhost:3306/test?useUnicode=true&characterEncoding=gbk"/>
<property name="javax.persistence.jdbc.user"
value="root"/>
<property name="javax.persistence.jdbc.password"
value="123"/>
</properties>
</persistence-unit>
</persistence>
测试类
public class test {
public static void main(String[] args) {
EntityManagerFactory emf = Persistence.createEntityManagerFactory("jpaUnit");
EntityManager em = emf.createEntityManager();
Query query = em.createQuery("select * from user");
List<User> users = query.getResultList();
for(User u:users)
{
System.out.println(u.getId()+","+u.getName()+","+u.getPass()+","+u.getPhone());
}
}
}