C#通过Process启动其他程序遇到的疑问！

[闷头挣钱]

        private void BTN_START_Click(object sender, EventArgs e)
        {
            new Thread(delegate()
            {
                Process m_Process =  new Process();
                m_Process.StartInfo.FileName = “help”;//这个可以正常输出，与控制台输出一致
//m_Process.StartInfo.FileName = "java";//这个没有输出，为啥？与控制台输出不一致
                m_Process.StartInfo.UseShellExecute = false;
                m_Process.StartInfo.RedirectStandardOutput = true;
                m_Process.StartInfo.CreateNoWindow = true;
                m_Process.OutputDataReceived += new DataReceivedEventHandler(Process_OutputDataReceived);
                m_Process.Start();
                m_Process.BeginOutputReadLine();
                m_Process.WaitForExit();
                m_Process.Close();
            }).Start();
        }

        public delegate void OutputText(string text);
        void Process_OutputDataReceived(object sender, DataReceivedEventArgs e)
        {
            OutputText dl = new OutputText(delegate(string text)
            {
                if (text == null) return;
                C_CONSOLE.AppendText(text);
                C_CONSOLE.AppendText("\r\n");
                C_CONSOLE.ScrollToCaret();
            });
            C_CONSOLE.BeginInvoke(dl, e.Data);
        }

[wind_cloud2011]

哪里出错？

[闷头挣钱]

呵呵，刚刚发出帖子我就找到问题了

[闷头挣钱]

他喵的java标准输出用的是Error m_Process.ErrorDataReceived += m_Process_ErrorDataReceived; m_Process.BeginErrorReadLine(); 加上这两句就好使了