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$link = $_GET['link'];
$con = mysql_connect("localhost", "mysql_user", "mysql_password");
mysql_select_db("database", $con);
$result = mysql_query("SELECT * FROM 某表 where 某字段='$link'", $con);
$num_rows = mysql_num_rows($result);
if($num_rows > 0){
跳转...
}else{
echo "显示域名非法";
}