linux shell脚本中函数调用问题

[ElenaYu]

下面的代码中怎么在上面的if语句中调用checkall函数，我这样写的有问题，求指点！不甚感激~
#!/bin/bash
processer=$1
if [ $1 = "all" ];then
checkall
fi
checkall()
{
count1=`ps -ef |grep @name |grep -v "grep" |wc -l`
#echo $count1
count2=`ps -ef |grep @name |grep -v "grep" |wc -l`
#echo $count2

if [ $count1 == 0 ] && [ $count2 == 0 ];then
sleep 2
echo "successfully!"
else
echo "failed!"
exit 1
fi
}

[HBack]

把checkall函数放在if的前面

[奔跑的路]

#!/bin/bash
processer=$1
checkall()
{
       count1=`ps -ef |grep @name  |grep -v "grep" |wc -l`
       #echo $count1
       count2=`ps -ef |grep @name  |grep -v "grep" |wc -l`
       #echo $count2

       if [ $count1 == 0 ] && [ $count2 == 0 ];then
             sleep 2 
             echo "successfully!"          
       else 
             echo "failed!"
             exit 1
       fi
}

if [ $1 = "all" ];then
    checkall
fi