帮我写一个正则表达式取第二个圆括号中的值把，急求！

zjd1121 2015-02-09 03:04:08

String s =" Platform Software
VRP (R) software, Version 8.100 (CE6850EI V100R005C10)
Copyright (C) 2012-2015 Technologies Co., Ltd.HUAWEI CE6850-48T4Q-EI uptime is 1 day, 2 hours, 57 minutes CE6850-48T4Q-EI(Master) 3 : uptime is 1 day, 2 hours, 57 minutes
StartupTime 2015/02/04 09:07:56
Memory Size : 2048 M bytes
Flash Size : 1024 M bytes
NVRAM Size : 512 K bytes

我想取第二个圆括号中的值CE6850EI V100R005C10，这个正则怎么写啊？

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liangtu 2015-02-11

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import org.apache.commons.lang.StringUtils;

String[] arr = StringUtils.substringsBetween(testStr, "(", ")");
System.out.println(arr[1]);//第二个

ae8686886 2015-02-09

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String str1="Platform SoftwareVRP (R) software, Version 8.100 (CE6850EI V100R005C10)Copyright (C) 2012-2015 Technologies Co., Ltd.HUAWEI CE6"; int i = str1.indexOf("(",str1.indexOf("(")+1); int j = str1.indexOf(")",str1.indexOf(")")+1); String str2 = str1.substring(i+1,j); System.out.println(str2);

isoftstone57226 2015-02-09

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好多写法啊，来个最笨的 Pattern pattern = Pattern.compile("Version 8.100\\s+\\((.*)\\)Copyright"); Matcher matcher = pattern.matcher(s); StringBuffer sbr = new StringBuffer(); if (matcher.find()) { System.out.println(matcher.group(1));

slwsss 2015-02-09

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Matcher m=Pattern.compile(".*?\\).*?\\(([^)]*?)\\)").matcher(s); if(m.find())System.out.println(m.group(1));

sca4441479 2015-02-09

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final String REGEX=".*(\\(.*\\))Copyright.*";
		String str1="Platform SoftwareVRP (R) software, Version 8.100 (CE6850EI V100R005C10)Copyright (C) 2012-2015  Technologies Co., Ltd.HUAWEI CE6";
		Matcher m=Pattern.compile(REGEX, Pattern.CASE_INSENSITIVE).matcher(str1);
		if(m.find()){
			System.out.println(m.group(1).replace("(", "").replace(")", ""));
		}