创建Service的问题？请帮看看？

[ynduanlian]

我在MainActivity创建同时启动一个（从网络上接收消息）的服务：

    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        
        Intent it=super.getIntent();
        String strShopURL=it.getStringExtra("shop_url");
        String StrUID=it.getStringExtra("UID");
        String StrPWD=it.getStringExtra("PWD");
        

        Intent intent=new Intent(MainActivity.this,OrderService.class);
        String url2=new StringBuilder(strShopURL).append(this.getString(R.string.message_url))
				.append("?UID=").append(StrUID).append("&PWD=").append(StrPWD).toString();	
        intent.putExtra("URL", url2);
        startService(intent);
    }

服务的代码大概是这样：

public class OrderService extends Service{
    public static final String SETTING_FILE="Config";
	public static final String SETTING_UID="UID";
	public static final String SETTING_PWD="PWD";
	private boolean threadDisable;
	private NotificationManager notificationManager;
	private SharedPreferences settings;
	private String strURL;
	
	@Override
	public IBinder onBind(Intent intent){
		return null;
	}
	
	@Override
	public void onCreate(){
		super.onCreate();
	}
	
	public void onStart(Intent intent, int startId) {
        super.onStart(intent, startId);
        strURL = intent.getStringExtra("URL");
        Log.d("Service_URL",strURL);

        notificationManager=(NotificationManager) this.getSystemService(NOTIFICATION_SERVICE);
		
		new Thread(new Runnable(){
			@Override
			public void run(){
				while(!threadDisable){
					try{
						Log.d("Begin_try",strURL);
						String StrTmp=getOrders(strURL);
						if (!StrTmp.equals("")){
							Notification notification2=new Notification();
							String ringName=RingtoneManager.getActualDefaultRingtoneUri(OrderService.this, RingtoneManager.TYPE_NOTIFICATION ).toString();
							notification2.sound=Uri.parse(ringName);
							notificationManager.notify(0,notification2);

							Notification notification1=new Notification();
							notification1.icon=R.drawable.ic_launcher;
							notification1.tickerText=StrTmp;
							PendingIntent intent=PendingIntent.getActivity(OrderService.this,0, new Intent(OrderService.this,MainActivity.class), 0);
							notification1.setLatestEventInfo(OrderService.this, "通知", "您收到："+StrTmp+" 个新订单", intent);
							notificationManager.notify(0,notification1);
						}
						Thread.sleep(60000);
					}catch(InterruptedException e){
						Toast.makeText(getApplicationContext(), e.toString(), Toast.LENGTH_SHORT).show();
					}
				}
			}
		}).start();
        
}	
	
	@Override
	public void onDestroy(){
		super.onDestroy();
		this.threadDisable=true;
	}
	
	private String getOrders(String strURL){
		String res="";
		
		try{
			HttpClient httpClient=new DefaultHttpClient();
			HttpGet httpGetRequest=new HttpGet(strURL);
			Log.d("BeginGet","BeginGet");
			HttpResponse response=httpClient.execute(httpGetRequest);
			Log.d("EndGet",response.getStatusLine().toString());
			if(HttpStatus.SC_OK==response.getStatusLine().getStatusCode()){
				String responseMsg=EntityUtils.toString(response.getEntity());
				res=responseMsg;
			}
		}catch(ClientProtocolException e){
			e.printStackTrace();
		}catch(IOException e){
			e.printStackTrace();
		}catch(Exception e){	
			Toast.makeText(getApplicationContext(), e.toString(), Toast.LENGTH_SHORT).show();
		}
		return res;
	}
}

那么：当用户切换到别的APP后，又切换回本APP，是不是会再次执行MainActivity的OnCreate ?而服务此时已经在运行，再次
StartService是不会导致错误？如果会，如何解决？

[画虎烂]

1、切换回本APP，如果MainActivity没把杀死的话，它是不会执行OnCreate的，会调用onResume 2、Service的OnCreate只会执行一次，onStart是每次startService都会执行

[bdmh]

service即使多次被startservice启动，也只会执行一次create activity只要没被杀死或回收，不会再次执行create

[windfury_plus]

同意1、2楼的回答

[IT界的吉祥物]

将网络操作放的onCreat中去实现