Linux shell script unexpected operator问题

[zhangrongchao_]

下面是一段shell脚本，根据输入来判断输出；

#2015/02/21  ZRC   First Relearse
PATH=/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/usr/local/games
export PATH

read -p "please input (Y/N):" yn
[ "$yn" == "Y" ] || [ "$yn" == "y" ] && echo "OK, continue" && exit 0
[ "$yn" == "N" ] || [ "$yn" == "n" ] && echo "Oh, interrupt!" && exit 0
echo "I do not know  what your choice is " && exit 0

我输入“y"后，出现以下错误。百思得其解；
please input (Y/N):n
sh06-2.sh: 8: [: n: unexpected operator
sh06-2.sh: 8: [: n: unexpected operator
sh06-2.sh: 12: [: n: unexpected operator
sh06-2.sh: 12: [: n: unexpected operator
I do not know what your choice is

请问问题出在哪？

[iasky]

我这里默认bash是没有问题的，你在第一行加入 #!/bin/bash

[ljc007]

我的RHEL5里面测试没有问题 你用的什么操作系统？

[QKForex]

可能是脚本编码格式的问题 执行以下命令试试 dos2unix script.sh 再重新执行看看