100分解决一个python读取txt文件，且能知道是读取到哪一行了,多谢

[jikikiji]

数据样本是（txt文件）
89 98 100 63
76 88 97 68
56 65 78 100
.....
我现在想输出所有行第一个域的数值，以及第三个域的内容，并且需要把第一行和第二行对应的域相减，第二行和第三行相减，目前思路没了，只能做到输出第一个域和第三个域，如何把第一行和第二行相减并输出呢，请各位大侠指教，谢啦
#!/usr/bin/env python
# -*- coding: gbk -*-
#读取文件
import re
import os
for a in getFileList(r'E:\数据'):
with open('E:\\数据\\'+ a , 'r') as f:
for line in f.readlines():
bbb = line.split()[0]
ccc = line.split()[1]
print bbb,ccc

[jiht594]

for a in getFileList(r'E:\数据'): count=0 #count + 1就是当前行 bufferLines #把所用行都存起来 with open('E:\\数据\\'+ a , 'r') as f: for line in f.readlines(): bufferLines[count] = line if count>0: 用buerLines[count-1]中的数减去bufferLines[count] count = count + 1 bbb = line.split()[0] ccc = line.split()[1] print bbb,ccc

[jikikiji]

多谢jiht594和xmnathan指导，我运行了下，提示如下错误，bufferLines是哪个模块里的？ Traceback (most recent call last): File "E:\python\test.py", line 54, in <mod bufferLines #把所用行都存起来 NameError: name 'bufferLines' is not defined

[惟愿莲心不染尘]

思路就是至少要临时保存前一行的数据， 当读取到第二行的时候就和缓存的第一行的数据进行运算， 运算完将缓存数据换成第二行的依次类推。 ls的保存所有行的方法也可行。

[jiht594]

引用 3 楼 jikikiji 的回复:

多谢jiht594和xmnathan指导，我运行了下，提示如下错误，bufferLines是哪个模块里的？ Traceback (most recent call last): File "E:\python\test.py", line 54, in <mod bufferLines #把所用行都存起来 NameError: name 'bufferLines' is not defined

上面的相当于伪代码 试试这个

for a in getFileList(r'E:\数据'):
    count=0 #count + 1就是当前行
    bufferLines = {} #把所用行都存起来    
    with open('E:\\数据\\'+ a , 'r') as f:
        for line in f.readlines():
            bufferLines[count] = line
            if count>0: #用buerLines[count-1]中的数减去bufferLines[count]
                numbers1 = bufferLines[count - 1].split()
                numbers2 = bufferLines[count].split()
                print "difference:" , int(numbers1[0]) - int(numbers2[0]), int(numbers1[1]) - int(numbers2[1]), int(numbers1[2]) - int(numbers2[2]), int(numbers1[3]) - int(numbers2[3] )
            count = count + 1
            bbb = line.split()[0]
            ccc = line.split()[1]
            print bbb,ccc

[jiht594]

贴一下我的测试代码, 你要是弄不好我也没办法了 文件路径: E:\\1.txt 数据就是1楼的三行: 89 98 100 63 76 88 97 68 56 65 78 100 输出结果: 89 98 difference: 13 10 3 -5 76 88 difference: 20 23 19 -32 56 65

# coding=utf8
count=0 #count + 1就是当前行
bufferLines = {} #把所用行都存起来
with open('E:\\1.txt' , 'r') as f:
    for line in f.readlines():
        bufferLines[count] = line
        if count>0: #用buerLines[count-1]中的数减去bufferLines[count]
            numbers1 = bufferLines[count - 1].split()
            numbers2 = bufferLines[count].split()
            print "difference:" , int(numbers1[0]) - int(numbers2[0]), int(numbers1[1]) - int(numbers2[1]), int(numbers1[2]) - int(numbers2[2]), int(numbers1[3]) - int(numbers2[3] )
        count = count + 1
        bbb = line.split()[0]
        ccc = line.split()[1]
        print bbb,ccc

[jikikiji]

多谢jiht594大侠，已经ok，马上结贴

[jikikiji]

非常感谢答复，我运行了修改后的脚本，没有获得结果输出 for a in getFileList(r'E:\数据'): count=0 #count + 1就是当前行 bufferLines = {}#把所用行都存起来 with open('E:\\数据\\'+ a , 'r') as f: for line in f.readlines(): bufferLines[count] = line if count>0: #用buerLines[count-1]中的数减去bufferLines[count] numbers1 = bufferLines[count - 1].split() numbers2 = bufferLines[count].split() print "difference:" , int(numbers1[0]) - int(numbers2[0]), int(numbers1[1]) - int(numbers2[1]), int(numbers1[2]) - int(numbers2[2]), int(numbers1[3]) - int(numbers2[3] ) count = count + 1 bbb = line.split()[0] ccc = line.split()[1] print 22222 print bbb,ccc print 1111 得到的结果是 E:\python>test.py 1111