easyui dialog 弹窗下上传图片没有反映

[g000zjy]

我用的easyui 然后 用的dialog弹窗， 然后我上传图片没反应。。下面是代码。。

    <div id="toolbar">
        <a href="javascript:void(0)" class="easyui-linkbutton" iconCls="icon-edit" plain="true" onclick="edit()">新闻图片修改</a>
    </div>
    <div id="dlg" class="easyui-dialog" style="width:400px;height:200px;padding:10px 20px"
            closed="true" buttons="#dlg-buttons">
        <div class="ftitle">图片管理</div>
        <form id="fm" method="post" enctype="multipart/form-data" novalidate>
            <div class="fitem">
                <label>上传图片:</label>
                <input name="pic" type="file">
            </div>
        </form>
    </div>
        <div id="dlg-buttons">
        <a href="javascript:void(0)" class="easyui-linkbutton c6" iconCls="icon-ok" onclick="save()" style="width:90px">保存</a>
        <a href="javascript:void(0)" class="easyui-linkbutton" iconCls="icon-cancel" onclick="javascript:$('#dlg').dialog('close')" style="width:90px">取消</a>
    </div>

        function edit(){
            var row = $('#dg').datagrid('getSelected');
            if (row){
                $('#dlg').dialog('open').dialog('setTitle','修改图片');
                $('#fm').form('load',row);
                url = '../php/show_pic.php?o=edit&nid='+row.nid;
            }
        }
        function save(){
            $('#fm').form('submit',{
                url: url,
                onSubmit: function(){
                    return $(this).form('validate');
                },
                success: function(result){
                    $('#dlg').dialog('close');  
                    $('#dg').datagrid('reload');
                }
            });
        }

		$file = $_FILES["file"]["name"];
		$url = "http://localhost/web/admin/images/";
		if ($_FILES["file"]["error"] > 0){
			echo "Return Code: " . $_FILES["file"]["error"] . "<br />";
		}else{
			if (file_exists("../images/" . $_FILES["file"]["name"])){
		    	echo $_FILES["file"]["name"] . " already exists. ";
		    }else{
			    move_uploaded_file($_FILES["file"]["tmp_name"],"../images/" . $_FILES["file"]["name"]);
			      
			    $sql="insert into xs_pic(tofrom,pic) values('$tofrom','".$url.$file."')";
			    if(execute_data($sql)){
			    	echo 'ok';
			    	// echo $url.$file;
			    }else{
			    	echo 'error';
			    }
		    }	
		}

	function execute_data($sql){
		$result = @mysql_query($sql) or die(mysql_error());
		// @mysql_free_result($result) or die(mysql_error());
		return $result;
	}

[一起混吧]

控制台下看看有没有报错

[人鱼传说]

没反应说明有执行错误，可用浏览器的控制台跟踪一下，看有什么错误!