scanner类输入三个数，在输入不是数的情况下如何重新要求输入这三个数

[乐百川]

public class Test1 {
	public  void main(String... args) {
		Scanner scanner = new Scanner(System.in);
		double a, b, c;
		a = b = c = 0;
		boolean isWrongInput = true;
		do {
			try {
				System.out.print("Please input a,b and c:");
				a = scanner.nextDouble();
				b = scanner.nextDouble();
				c = scanner.nextDouble();
				isWrongInput = false;
			} catch (InputMismatchException e) {
				System.out.println("Wrong input!Please try again.");
				scanner.reset();
			} catch (Exception e) {
				e.printStackTrace();
				throw e;
			}

		} while (isWrongInput == true);
		double delta = b * b - 4 * a * c;
		double x1, x2;
		if (delta == 0) {
			x1 = x2 = (-b) / (2 * a);
			System.out.println("x1=x2=" + x1);
		} else if (delta > 0) {
			x1 = (-b + Math.sqrt(delta)) / (2 * a);
			x2 = (-b - Math.sqrt(delta)) / (2 * a);
			System.out.println("x1=" + x1);
			System.out.println("x2=" + x2);
		} else {
			double real, imagine;
			real = -b / (2 * a);
			imagine = Math.sqrt(-delta) / (2 * a);
			System.out.printf("x1=%s\nx2=%s\n",
					"" + real + "+" + imagine + "i", "" + real + "-" + imagine
							+ "i");
		}
	}
}

我这样，输入如果用字母的话就直接死循环了，求教

[三仙半]

把scanner = new Scanner(System.in);拿到do-while循环里面去

[wyc_]

先用hasNextDouble()判断一下，再nextDouble()

[bbjiabcd]

scanner.reset();改为scanner.nextLine();