求助ajax 请求不到 servlet

l清水 2015-05-03 11:10:04

web.xml
<servlet>
<servlet-name>SPaction</servlet-name>
<servlet-class>com.mdl.platform.LeftNavAction</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>SPaction</servlet-name>
<url-pattern>/SPaction</url-pattern>
</servlet-mapping>

js
<script>
function getAjaxRequest() {
if (window.XmlHttpRequest) {
return new XMLHttpRequest();
} else {
try {
return new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
try{
return new ActiveXObject("Microsoft.XMLHTTP");
}catch(e){
alert("cuowiu");
}
}
}
}

function ajaxmenu(Idate) {
var ajax = getAjaxRequest();
var url = "${pageContext.request.contextPath}/SPaction";
alert(url);
ajax.open("get", url, false);
ajax.onreadystatechange = function() {
if(ajax.readystate==4){
//alert(ajax.status);
if(ajax.status==200){
var result = ajax.responseText.split("_FG_") ;
alert(result);
var father = document.findElmentById("Left-one");
for(index=0 ;index < result.length; index++){
var temp = document.createElement("div");
temp.innerText = result[index];
father.appendChild(temp);
}
}

}
}
ajax.send(null);
}
</script>

servlet
protected void doGet(HttpServletRequest request,
HttpServletResponse response) throws ServletException, IOException {
System.out.println("----------como in ------------");
String actionType = request.getParameter("actionType");
System.out.println("----------" + actionType);
if (actionType == null||"".equals(actionType.trim()) ) {
System.out.println("这是一次请求");
} else {
System.out.println("left");
exeFindLeftNav(request, response);
}

}

问题来了，我直接请求servlet 是好使，但是ajax不好使，打印的result 为空，而且serlet中的come in 也没有打印。
url 打印了是/frame/SPaction 这个是正确的。

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