怎么定义一个静态方法返回类自身？

[qq120848369]

类似这种感觉：

class User {
public static function test() { return self; }
public static function do() {}
}

User::test()::do();

[qq120848369]

引用 1 楼 xuzuning 的回复:

只能这样

class User {
  public static function test() {
    return new self;
  }
  public static function do0() {
    echo __METHOD__;
  }
}

$p = User::test()->do0();

User::do0

噢噢，只能返回对象这样。

[xuzuning]

只能这样

class User {
  public static function test() {
    return new self;
  }
  public static function do0() {
    echo __METHOD__;
  }
}

$p = User::test()->do0();

User::do0