求教 JS正则的如何表达？

[zhongabci9]

学习JS时间不长，对数据逻辑运用不是很清晰，如何做到修改存放在input中的数据，比如我提交了一个pars=“数据”
数据结构=“id=1431243414017&start_date=2015-05-10 09:55&end_date=2015-05-10 11:40&text=新建日程&details=undefined | ”
原数据：
parsA=“id=1431243414017&start_date=2015-05-10 09:55&end_date=2015-05-10 11:40&text=新建日程&details=undefined | id=1431243414021&start_date=2015-05-10 12:00&end_date=2015-05-10 15:30&text=新建日程&details=undefined | id=1431243414022&start_date=2015-05-10 12:25&end_date=2015-05-10 18:00&text=新建日程&details=undefined | id=1431243414023&start_date=2015-05-10 09:15&end_date=2015-05-10 11:20&text=新建日程&details=undefined | id=1431243414024&start_date=2015-05-10 16:25&end_date=2015-05-10 19:40&text=新建日程&details=undefined | “

如何才能以id=1431243414017 作为一个条件，原数据存在同样的ID替换“start_date=2015-05-10 09:55&end_date=2015-05-10 11:40&text=新建日程&details=undefined | ”

如果如果不存在则新增：原数据+Pars

刚学JS求教一下高手，这个逻辑怎么写?

[zhongabci9]

原数据： parsA="id=1431243414017&start_date=2015-05-10 09:55&end_date=2015-05-10 11:40&text=新建日程&details=undefined |id=1431243414021&start_date=2015-05-10 12:00&end_date=2015-05-10 15:30&text=新建日程&details=undefined |id=1431243414022&start_date=2015-05-10 12:25&end_date=2015-05-10 18:00&text=新建日程&details=undefined |id=1431243414023&start_date=2015-05-10 09:15&end_date=2015-05-10 11:20&text=新建日程&details=undefined |id=1431243414024&start_date=2015-05-10 16:25&end_date=2015-05-10 19:40&text=新建日程&details=undefined |" var parsA=document.getElementById('getvalue').value parsB=pars.substr(16) if(parsA.indexOf(parsB) > 0 ) { alert('删除字符串，如何从匹配"ID=13位数字"删除到 " |"'); }; 如果parsB=“id=1431243414023” 存在于parsA 则删除“id=1431243414023&start_date=2015-05-10 09:15&end_date=2015-05-10 11:20&text=新建日程&details=undefined |” 这个正则怎么写呢？向高手请教一下。

[天际的海浪]

parsA=parsA.replace(new RegExp(parsB+".+?\\|","ig"),"");

[zhongabci9]

谢谢您，能帮看看

[zhongabci9]

var parsA=document.getElementById('getvalue').value parsB=pars.substr(16) parsC=" |" if(parsA.indexOf(parsB) > 0 ) { parsA=parsA.replace(new RegExp(parsB+".+?\\|","ig"),""); }; document.getElementById('getvalue').value =parsA+pars+" |"; 匹配的数据没删除，不知道是那里错了呢？

[天际的海浪]

var parsB=pars.substr(0,16);

[zhongabci9]

谢谢浪兄！我测试了提示，不知怎么的，好像没有根据parsB=“ id=1431243414021”删除 “id=1431243414021&start_date=2015-05-10 12:00&end_date=2015-05-10 15:30&text=新建日程&details=undefined |” parsA="id=1431243414017&start_date=2015-05-10 09:55&end_date=2015-05-10 11:40&text=新建日程&details=undefined |id=1431243414021&start_date=2015-05-10 12:00&end_date=2015-05-10 15:30&text=新建日程&details=undefined | alert(new RegExp(parsB+"\\ |","ig"),""); 提示为： /id=1431265720669\ |gi 怎么样才能获得正则值为要删除的：“id=1431243414021&start_date=2015-05-10 12:00&end_date=2015-05-10 15:30&text=新建日程&details=undefined |”

[zhongabci9]

目的是想 让ID 值有唯一性，重复值数据比较难处理。

[天际的海浪]

    var pars="id=1431243414021&aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa";
    var parsA="id=1431243414017&start_date=2015-05-10 09:55&end_date=2015-05-10 11:40&text=新建日程&details=undefined |id=1431243414021&start_date=2015-05-10 12:00&end_date=2015-05-10 15:30&text=新建日程&details=undefined |id=1431243414022&start_date=2015-05-10 12:25&end_date=2015-05-10 18:00&text=新建日程&details=undefined |id=1431243414023&start_date=2015-05-10 09:15&end_date=2015-05-10 11:20&text=新建日程&details=undefined |id=1431243414024&start_date=2015-05-10 16:25&end_date=2015-05-10 19:40&text=新建日程&details=undefined |";
    var parsB=pars.substr(0,16);
    if(parsA.indexOf(parsB) > 0 ) 
    { 
        parsA=parsA.replace(new RegExp(parsB+".+?\\|","ig"),"");
    };
    parsA=parsA+pars+" |";
	alert(parsA);

[zhongabci9]

谢谢浪兄！今晚我学习一下这个方法。