sql server求分组最大值，最小值，最大值对应时间，和最小值对应时间

[人生初见]

我需要分组查询13301,13302的最大值，最大值对应的时间，最小值，最小值对应的时间，这个改怎么写

[人生初见]

有没有人能帮帮忙，谢谢啦

[人生初见]

有没有人能帮帮忙，谢谢啦

[人生初见]

有没有人能帮帮忙，谢谢啦

[还在加载中灬]

;WITH CTE AS(
	SELECT senid,minv,maxv,maxt,mint
		,ROW_NUMBER()OVER(PARTITION BY senid ORDER BY minv)minRN
		,ROW_NUMBER()OVER(PARTITION BY senid ORDER BY maxv DESC)maxRN
	FROM TB
)
SELECT T1.senid,T1.minv,T1.mint,T2.maxv,T2.maxt
FROM CTE T1
	JOIN CTE T2 ON T1.senid=T2.senid
WHERE T1.minRN=1 AND T2.maxRN=2

[在路上_-]

试试

;with t AS
(
select senid, MAX(maxv) maxv, MIN(minv) minv
from tb
group by senid
)
select t.senid, t.maxv, tb.maxt, t.minv, t2.mint
from t JOIN tb ON tb.senid=t.senid AND tb.maxv=t.maxv
  JOIN tb t2 ON t2.senid=t.senid AND t2.minv=t.minv

[人生初见]

楼上的方法用了，没有查出来

[在路上_-]

楼主给生成测试数据的语句吧

[在路上_-]

;with t AS
(
select senid, MAX(maxv) maxv, MIN(minv) minv
from tb
group by senid
)
select t.senid, t.maxv, MAX(tb.maxt) maxt, t.minv, MIN(t2.mint) mint
from t JOIN tb ON tb.senid=t.senid AND tb.maxv=t.maxv
  JOIN tb t2 ON t2.senid=t.senid AND t2.minv=t.minv
group by t.senid, t.maxv,  t.minv

如果最大值对应两个或以上的时间，取最大时间吗？ 最小值也有同样问题

[人生初见]

引用 8 楼 xxzxwsx 的回复:

;with t AS
(
select senid, MAX(maxv) maxv, MIN(minv) minv
from tb
group by senid
)
select t.senid, t.maxv, MAX(tb.maxt) maxt, t.minv, MIN(t2.mint) mint
from t JOIN tb ON tb.senid=t.senid AND tb.maxv=t.maxv
  JOIN tb t2 ON t2.senid=t.senid AND t2.minv=t.minv
group by t.senid, t.maxv,  t.minv

如果最大值对应两个或以上的时间，取最大时间吗？ 最小值也有同样问题

如果最大值有多个时间，取其中一个

[人生初见]

如果按照senid还有时间按照月的分组，求最大值，最小值，最大值对应时间，最小值对应时间改怎么写

[还在加载中灬]

;WITH CTE AS(
	SELECT senid,minv,maxv,maxt,mint
		,CONVERT(VARCHAR(7),mint,120)minM
		,CONVERT(VARCHAR(7),maxt,120)maxM
		,ROW_NUMBER()OVER(PARTITION BY senid,CONVERT(VARCHAR(7),mint,120) ORDER BY minv)minRN
		,ROW_NUMBER()OVER(PARTITION BY senid,CONVERT(VARCHAR(7),maxt,120) ORDER BY maxv DESC)maxRN
	FROM TB
)
SELECT T1.senid,T1.minv,T1.mint,T2.maxv,T2.maxt
FROM CTE T1
	JOIN CTE T2 ON T1.senid=T2.senid AND T1.minM=T2.maxM
WHERE T1.minRN=1 AND T2.maxRN=1

[gw6328]

;with cte as(
	select *,rn1=ROW_NUMBER() over(partition by senid order by minv asc),rn2=ROW_NUMBER() over(partition by senid order by maxv desc) from tb
)
select senid,min(minv)as minv,max(maxv) as maxv,max(case when rn1=1 then mint else '1900-01-01'end) as maxt,max(case when rn2=1 then mint else '1900-01-01' end) as maxt  from cte
group by senid 

[习惯性蹭分]

try this

;with t1 as(
select * from tab a where not exists(select 1 from tab where senid=a.senid and minv>a.minv)
),t2
as(
select * from tab a where not exists(select 1 from tab where senid=a.senid and maxv<a.mav)
)
select isnull(t1.senid,t2.senid) as senid,t1.minv,t1.mint,t2.maxv.t2.maxt
from t1 
full join t2
on t1.senid=t2.senid