两个json，结构不一样，值是一样的，怎么对比让他们相等？

[bzzzzzzzzz]

public static void main(String[] args) {

String str = "{\"name\":\"Michael\",\"address\":{\"city\":\"Beijing\",\"street\":\" Chaoyang Road \",\"postcode\":100025}}";
String strTwo = "{\"address\":{\"city\":\"Beijing\",\"street\":\" Chaoyang Road \",\"postcode\":100025},\"name\":\"Michael\"}";
System.out.println(compareJson(str,strTwo));
}
str 和 StrTwo应该是相同的

compareJson(str1,str2);
方法如何写？

[bdmh]

转成对象，然后比较里面的字段值

[xuzuning]

转成队形再比较

[Imcx]

对象取出来放数组里，再进行对比 参考

[Imcx]

的字段值

[showjim]

试试fastCSharp

        struct x
        {
            public string name;
            public y address;
        }
        struct y
        {
            public string city;
            public string street;
            public int postcode;
        }

            string str = "{\"name\":\"Michael\",\"address\":{\"city\":\"Beijing\",\"street\":\" Chaoyang Road \",\"postcode\":100025}}";
            string strTwo = "{\"address\":{\"city\":\"Beijing\",\"street\":\" Chaoyang Road \",\"postcode\":100025},\"name\":\"Michael\"}";
            Console.WriteLine(fastCSharp.emit.equals<x>.Equals(fastCSharp.emit.jsonParser.Parse<x>(str), fastCSharp.emit.jsonParser.Parse<x>(strTwo)));

[娃都会打酱油了]

[刘欣的博客]

using Newtonsoft.Json;
using Newtonsoft.Json.Converters;


    public class farm
    {
        public int id { get; set; }
        public string utime { get; set; }
        public string playername { get; set; }
        public string farmname { get; set; }
        public int zlevel { get; set; }
        public int blood { get; set; }
        public int x { get; set; }
        public int y { get; set; }
        public int rice { get; set; }
        public int stat { get; set; }
        public int speed { get; set; }
        public int step { get; set; }
        public string pic { get; set; }
        public int maxstorage { get; set; }
        public int workstep { get; set; }
        public int riceoutput { get; set; }
        public string zmessage { get; set; }
    }


 List<farm> tmplist = JsonConvert.DeserializeObject<List<farm>>(s);

[衣舞晨风]

1、将json转成datatablehttp://blog.csdn.net/jiankunking/article/details/42498673 2、比较datatable http://www.jb51.net/article/45978.htm